Javascript根据特定字符串对数组进行排序

Question

基本上，我正在尝试根据特定的字符串匹配对数组进行排序。我希望限定符 === 'oip' 排序到顶部

[
 {
  qualifier: 'abc',
 },
 {
  qualifier: 'oip'
 }
]

我将如何使用 x.sort((a,b) =>

Answer 1

应该这样做:

x.sort((a,b) => a === 'oip'? 1 : -1)

您可以阅读更多关于 sort here 的信息.

If a and b are two elements being compared, then:

• If compareFunction(a, b) is less than 0, sort a to an index lower than b (i.e. a comes first).
• If compareFunction(a, b) returns 0, leave a and b unchanged with respect to each other, but sorted with respect to all different elements. Note: the ECMAscript standard does not guarantee this behaviour, and thus not all browsers (e.g. Mozilla versions dating back to at least 2003) respect this.
• If compareFunction(a, b) is greater than 0, sort b to an index lower than a (i.e. b comes first).
• compareFunction(a, b) must always return the same value when given a specific pair of elements a and b as its two arguments. If inconsistent results are returned then the sort order is undefined.

此答案适用于 OP 所述的示例。然而，为了更完整(感谢指出 @Pointy )，这里是一个完整的版本:

x = [
 {qualifier: 'abc'},
 {qualifier: 'oip'},
 {qualifier: 'def'},
 {qualifier: 'gij'},
 {qualifier: 'oip'},
];

y = x.sort((a, b) => {
  if (a.qualifier === b.qualifier && a.qualifier === 'oip') {
    return 0;
  } else if (a.qualifier === 'oip') {
    return -1;
  } else if (b.qualifier === 'oip') {
    return 1;
  }else {
    return a.qualifier > b.qualifier? 1 : -1;
  }
});