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javascript - 如何从openlayers中连续的数组点绘制线串

转载 作者:行者123 更新时间:2023-11-30 07:49:30 25 4
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我试图在 openlayers 中使用连续的 Points 绘制 LineString 以赋予它动画的感觉,就像它从头到尾绘制一样。

我试图通过关注 this example 来实现它. OL2 的所有引用都转换为 OpenLayers 5,但绘制仍然应该发生一个点,然后是整个数组的下一个点,而不是一次。

在此处查找具有当前输出的代码 - my code .

[供引用] 这是我正在努力实现的Snake animation for leaflet .

最佳答案

仅使用线串的顶点不会产生流畅的动画。您可以在 OpenLayers 示例中看到 https://openlayers.org/en/v4.6.5/examples/feature-move-animation.html标记在直线部分移动得更快。如果您需要像 OpenLayers 2 示例中那样沿着直线平滑移动,您需要使用 .getCoordinateAt() 随时计算您应该在直线上的位置。这是一个基于标记动画示例的演示,但也计算显示蛇示例中的线串的顶点之间的位置。您还可以绘制自己的直线并观看它们的动画效果。

var style = new ol.style.Style({
stroke: new ol.style.Stroke({
width: 4,
color: 'red'
})
});

var raster = new ol.layer.Tile({
source: new ol.source.OSM()
});

var vector = new ol.layer.Vector({
source: new ol.source.Vector(),
style: style
});

var map = new ol.Map({
layers: [raster, vector],
target: 'map',
view: new ol.View()
});

var xhr = new XMLHttpRequest();
xhr.open('GET', 'https://raw.githubusercontent.com/IvanSanchez/Leaflet.Polyline.SnakeAnim/master/route.js');
xhr.onload = function() {
// read the route coordinates
eval(xhr.responseText);
// reverse the route
var geom = new ol.geom.LineString(route.reverse());
// change Lat/Lon to Lon/Lat
geom.applyTransform(function(c){ return c.reverse(); });
geom.transform('EPSG:4326', map.getView().getProjection());
map.getView().fit(geom.getExtent(), { size: map.getSize() });
var snake = new ol.Feature();
vector.getSource().addFeature(snake);
animate_line(snake, geom, 30000);
}
xhr.send();

function animate_line(feature, linestring, duration) {

var length = linestring.getLength();
var length_shown = 0;

var coords = linestring.getCoordinates();
var coords_shown = [coords[0], coords[0]];
var geom_shown = new ol.geom.LineString(coords_shown);
feature.setGeometry(geom_shown);

var coordcount = 1;
var start = new Date().getTime();
var listenerKey = map.on('postcompose', animate);

function animate() {

var elapsed = new Date().getTime() - start;
var toAdd = length*elapsed/duration - length_shown;
var point = linestring.getCoordinateAt(Math.min(elapsed/duration, 1));

// restart from last intermediate point and remove it
var newPart = new ol.geom.LineString(coords_shown.slice(-1));
coords_shown.pop();

// add vertices until required length exceeded
while (coordcount < coords.length && newPart.getLength() <= toAdd) {
newPart.appendCoordinate(coords[coordcount]);
coords_shown.push(coords[coordcount]);
coordcount++;
}

// replace overrun vertex with intermediate point
coords_shown.pop();
coordcount--;
coords_shown.push(point);

geom_shown.setCoordinates(coords_shown);
length_shown += toAdd;

if (elapsed > duration) {
ol.Observable.unByKey(listenerKey);
}
map.render();

}

}

draw = new ol.interaction.Draw({
source: vector.getSource(),
type: 'LineString'
});

draw.on('drawend',function(evt){
geom = evt.feature.getGeometry();
evt.feature.setGeometry(undefined);
animate_line(evt.feature, geom, 6000);
});
map.addInteraction(draw);
html, body, .map {
margin: 0;
padding: 0;
width: 100%;
height: 100%;
}
<link href="https://cdn.rawgit.com/openlayers/openlayers.github.io/master/en/v5.3.0/css/ol.css" rel="stylesheet" />
<script src="https://cdn.rawgit.com/openlayers/openlayers.github.io/master/en/v5.3.0/build/ol.js"></script>
<div id="map" class="map"></div>

关于javascript - 如何从openlayers中连续的数组点绘制线串,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/55587144/

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