java - 消除数组中重复对象的最佳方法

Question

我遇到了问题，需要一些帮助...

我的对象有名称、经度和纬度。我的问题是，我有一个包含所有对象的数组，现在(几乎)有重复项。

这意味着 long/lat 几乎相同但肯定是重复的。

如何过滤它们以获得包含唯一对象的列表？这是我到目前为止所做的...

public static Collection<Station> findDuplicates(Collection<Station> stations) {
    Collection<Station> uniqueList = new ArrayList<>();
    for (Station firstStation : stations) {
        Station tempStation = firstStation;
        for (Station secondStation : stations) {
            //Check if distance of the stations is less than 25m then we assume it's the same and we are going to merge the stations
            if ((distanceFrom(firstStation.getLatitude(), firstStation.getLongitude(), secondStation.getLatitude(), secondStation.getLongitude()) < 25)) {
                tempStation = mergeStation(firstStation, secondStation);
            }
        }
    }
    //How to find/add unique stations to uniqueList   
    return uniqueList;
}

提前致谢!

Answer 1

只需使用 Set 而不是 List 如下:

public static Collection<Station> findDuplicates(Collection<Station> stations) {
    Set<Station> uniqueList = new HashSet<>();
    // rest of your code
}

但是，要使此解决方案正常工作，覆盖 Station 的 equals 和 hashCode 非常重要。像这样:

    public class Station {
        private long latitude;
        private long longitude;

        Station(long latitude, long longitude) {
            this.latitude = latitude;
            this.longitude = longitude;
        }

        long getLatitude() {
            return latitude;
        }

        long getLongitude() {
            return longitude;
        }

        @Override
        public boolean equals(Object o) {
            if (this == o) {
                return true;
            }
            if (o == null || getClass() != o.getClass()) {
                return false;
            }
            Station station = (Station) o;
            return latitude == station.latitude &&
                longitude == station.longitude;
        }

        @Override
        public int hashCode() {
            return Objects.hash(latitude, longitude);
        }
    }