java - 代码在 IDE 中正确，但在 CodeChef 中出错

Question

我正在尝试解决 codechef 问题我能够在 IDE 中获得输出以及自定义输入，当我尝试使用那里的输入运行时它会给我错误

问题链接: https://www.codechef.com/problems/HS08TEST

代码:

    /* package codechef; // don't place package name! */

import java.util.*;
import java.lang.*;
import java.io.*;
import java.text.DecimalFormat;
/* Name of the class has to be "Main" only if the class is public. */
class Codechef
{
    public static void main (String[] args) throws java.lang.Exception
    {
        Scanner input = new Scanner(System.in); 
        int numberOne = input.nextInt();
        float numberTwo = input.nextFloat();
        float reduction = 0;
        float result = 0;
        DecimalFormat df2 = new DecimalFormat(".00");
        if(numberOne > 0 && numberOne <= 2000 & numberTwo >= 0 && numberTwo <= 2000){
        if(numberOne % 5 == 0){
            reduction = (float)numberOne+(0.50f);
            if(reduction <= numberTwo){
                result = numberTwo-reduction;

                System.out.println(df2.format(result));
            }
            if(reduction > numberTwo){
                System.out.println(df2.format(numberTwo));
            }
        }
        else{
            System.out.println(df2.format(numberTwo));
        }
        }

    }

}

错误:

Exception in thread "main" java.util.NoSuchElementException at java.util.Scanner.throwFor(Scanner.java:862) at java.util.Scanner.next(Scanner.java:1485) at java.util.Scanner.nextInt(Scanner.java:2117) at java.util.Scanner.nextInt(Scanner.java:2076) at Codechef.main(Main.java:14)

Answer 1

“错误”是由于输入无法解析为所需类型(即，Scanner 无法将输入解析为 int 或 float )

“A”解决方案是获取输入并手动解析它。您可以使用 nextLine 并在其上运行另一个 Scanner，或者在公共(public)分隔符上拆分，或者您可以简单地使用 next，例如.. .

import java.text.DecimalFormat;
import java.util.Scanner;

class Codechef {

    public static void main(String[] args) throws java.lang.Exception {
        Scanner input = new Scanner(System.in);
        String element = input.next(); // Next value up to the next space or new line...
        int numberOne = Integer.parseInt(element);
        element = input.next(); // Next value up to the next space or new line...
        float numberTwo = Float.parseFloat(element);
        float reduction = 0;
        float result = 0;
        DecimalFormat df2 = new DecimalFormat(".00");
        if (numberOne > 0 && numberOne <= 2000 & numberTwo >= 0 && numberTwo <= 2000) {
            if (numberOne % 5 == 0) {
                reduction = (float) numberOne + (0.50f);
                if (reduction <= numberTwo) {
                    result = numberTwo - reduction;

                    System.out.println(df2.format(result));
                }
                if (reduction > numberTwo) {
                    System.out.println(df2.format(numberTwo));
                }
            } else {
                System.out.println(df2.format(numberTwo));
            }
        }

    }

}

这假定输入通常在一行中提供，但此方法将允许您处理两个单独的输入。但是在不知道确切的输入是什么的情况下，很难提供更精确的解决方案