java - 尝试从 Controller 返回 html 页面时找不到资源

Question

我无法在 springboot 中呈现 html 页面。这是代码...

@RestController
    public class ProductController {
        @Autowired
        ProductService service;
    
        @InitBinder
        public void initBinder(WebDataBinder webDataBinder) {
            SimpleDateFormat dateFormat = new SimpleDateFormat("dd-MM-yyyy");
            dateFormat.setLenient(false);
            webDataBinder.registerCustomEditor(Date.class, new CustomDateEditor(dateFormat, true));
        }
        
        @RequestMapping(value = { "/", "/home" })
        public ModelAndView home() {
            System.out.println("sdasasas");
            return new ModelAndView("home");
        }
    
    

但每当我点击 http://localhost:8080/home 时，它​​都会显示以下日志

-8080-exec-4] o.s.w.s.v.ContentNegotiatingViewResolver : Selected 'text/html' given [text/html, application/xhtml+xml, image/webp, image/apng, application/signed-exchange;v=b3, application/xml;q=0.9,*/*;q=0.8]
2019-07-31 16:05:25.354 DEBUG 14850 --- [nio-8080-exec-4] o.s.w.servlet.view.InternalResourceView  : View name 'home', model {}
2019-07-31 16:05:25.354 DEBUG 14850 --- [nio-8080-exec-4] o.s.w.servlet.view.InternalResourceView  : Forwarding to [/WEB-INF/html/home.html]
2019-07-31 16:05:25.354 DEBUG 14850 --- [nio-8080-exec-4] o.s.web.servlet.DispatcherServlet        : "FORWARD" dispatch for GET "/WEB-INF/html/home.html", parameters={}
2019-07-31 16:05:25.356 DEBUG 14850 --- [nio-8080-exec-4] o.s.w.s.handler.SimpleUrlHandlerMapping  : Mapped to ResourceHttpRequestHandler ["classpath:/META-INF/resources/", "classpath:/resources/", "classpath:/static/", "classpath:/public/","/"]
2019-07-31 16:05:25.356  WARN 14850 --- [nio-8080-exec-4] o.s.w.s.r.ResourceHttpRequestHandler     : Path with "WEB-INF" or "META-INF": [WEB-INF/html/home.html]
2019-07-31 16:05:25.356 DEBUG 14850 --- [nio-8080-exec-4] o.s.w.s.r.ResourceHttpRequestHandler     : Resource not found
2019-07-31 16:05:25.357 DEBUG 14850 --- [nio-8080-exec-4] o.s.web.servlet.DispatcherServlet        : Exiting from "FORWARD" dispatch, status 404
2019-07-31 16:05:25.357 DEBUG 14850 --- [nio-8080-exec-4] o.j.s.OpenEntityManagerInViewInterceptor : Closing JPA EntityManager in OpenEntityManagerInViewInterceptor
2019-07-31 16:05:25.357 DEBUG 14850 --- [nio-8080-exec-4] o.s.web.servlet.DispatcherServlet        : Completed 404 NOT_FOUND
2019-07-31 16:05:25.357 DEBUG 14850 --- [nio-8080-exec-4] o.s.web.servlet.DispatcherServlet        : "ERROR" dispatch for GET "/error", parameters={}

Answer 1

对于必须返回 View 的基于 MVC 的应用程序，避免@RestController。它主要用于 REST API。 @Controller 可以返回一个 View

关于@RestController的更多信息:

• 这个注释是 @Controller 的一个特殊版本，它添加了@Controller 和 @ResponseBody 自动注解。所以我们不必将 @ResponseBody 添加到我们的映射方法中。这意味着@ResponseBody 默认激活。
• 如果你使用 @RestController 你不能返回一个 View (通过使用Viewresolver 在 Spring/Spring-Boot 中)
• @RestController 还将响应转换为 JSON/XML 自动，因为 @ResponseBody 使返回的对象成为可能在正文中的对象, 例如JSON 或 XML

Controller vs RestController

---

@RestController
    public class ProductController {
        @Autowired
        ProductService service;

        @RequestMapping(value = { "/", "/home" })
        public @ResponseBody ModelAndView home() {
            System.out.println("sdasasas");
            ModelAndView modelAndView = new ModelAndView();
            modelAndView.setViewName("home");
            return modelAndView;
        }
}

项目结构

无需指定spring.mvc.view.prefix=/WEB-INF/html/spring.mvc.view.suffix=.html

此外，请确保您没有任何带有 @EnableWebMvc 注释的附加类。这可能会弄乱 spring-boot 自动配置。