java - 可能的选择数量有限？

Question

这里是 Java 新手。

有这段代码(来自教程)，我想知道，我应该使用什么循环或其他方法来将最大猜测选择限制为例如 3？我的意思是用户只能猜测有限的次数，然后程序就会停止。

package com.company;

import java.util.Scanner;

public class Main {

    public static void main(String[] args) {
        int secretNum;
        int guess;
        boolean correct = false;

        Scanner keybord = new Scanner(System.in);
        System.out.print("GIVE ME SECRET NUMBER");
        secretNum = keybord.nextInt();

        while (!correct){
            System.out.println("GUESS: ");
            guess = keybord.nextInt();

            if (guess == secretNum){
                correct = true;
                System.out.println("YOU ARE RIGHT");
            }
            else if (guess < secretNum){
                System.out.println("HIGHER");
            }
            else if (guess > secretNum) System.out.println("LOWER");
        }
    }
}

Answer 1

您可以使用如下计数器跟踪尝试次数:

public static void main(String[] args) {
    int attempts = 0;
    Scanner keybord = new Scanner(System.in);
    System.out.print("GIVE ME SECRET NUMBER");
    int secretNum = keybord.nextInt();

    while (true){
        System.out.println("GUESS: ");
        int guess = keybord.nextInt();
        attempts++;

        if (guess == secretNum){
            System.out.println("YOU ARE RIGHT");
            break;
        }
        if (attempts == 3) {
            System.out.println("Max attempts!");
            break;
        }
        else if (guess < secretNum){
            System.out.println("HIGHER");
        }
        else if (guess > secretNum) System.out.println("LOWER");
    }
}