java - 我如何解析这个类似于 JSON 的字符串？

Question

在我的项目中，我向 Stripe 提交了一个请求，它返回了文件中的一组卡片

{
data = [{
    address_zip_check = null,
    country = US,
    last4 = 4242,
    funding = credit,
    metadata = {},
    address_country = null,
    address_state = null,
    exp_month = 4,
    exp_year = 2024,
    address_city = null,
    tokenization_method = null,
    cvc_check = pass,
    address_line2 = null,
    address_line1 = null,
    fingerprint = TAw8rdASXn64,
    name = null,
    id = card_1FiwAkASrE1bJO6aaQ,
    address_line1_check = null,
    address_zip = null,
    dynamic_last4 = null,
    brand = Visa,
    object = card,
    customer = cus_GDUhOvTHo9
}, {
    address_zip_check = null,
    country = US,
    last4 = 4444,
    funding = credit,
    metadata = {},
    address_country = null,
    address_state = null,
    exp_month = 4,
    exp_year = 2024,
    address_city = null,
    tokenization_method = null,
    cvc_check = pass,
    address_line2 = null,
    address_line1 = null,
    fingerprint = NW3wMUNiaA8g,
    name = null,
    id = card_1Fj3ZoASrE1bJO6aFu,
    address_line1_check = null,
    address_zip = null,
    dynamic_last4 = null,
    brand = MasterCard,
    object = card,
    customer = cus_GDUhOvTHo9
}], has_more = false, url = /v1/customers / cus_GDUhOvTHo9 / sources, object = list

}

问题是 JSONObject 和 JSONArray 无法将其识别为有效的 JSON。

JSONObject jsonObject = new JSONObject(jsonStr);
JSONArray jsonArray = jsonObject.getJSONArray("data");

"Expected literal value..."

我怎样才能解析这些信息？

有没有办法修改这个字符串，使其可以被识别为有效的 JSON？

我是否必须编写自己的解析方法？

Answer 1

returns back an array of cards on file

1. Stripe-API 返回有效的 json [1]。

2. 我猜失败发生在两者之间，例如当您将响应序列化到一个文件时。确保使用正确的 json 工具!

3. 您的打印看起来像一个普通的 Map.toString()。只需将 map 直接传递给 new JSONObject(mymap)。

[1] curl https://api.stripe.com/v1/customers -u sk_test_4eC39HqLyjWDarjtT1zdp7dc: