java - Scanner.nextLine();由于循环而在需要之前调用

Question

我有一个扫描仪input，它由我的Player 类中的getName() 调用。

public static String getName()
{
  System.out.println("Enter your character's name.");
   String n = input.nextLine();
  return n;
}

但是，当我使用循环来检查 RPG 类中是否有适当的玩家输入时，一切正常，直到我输入“n”或“N”代表

System.out.println("Confirm Character (Y/N)");
confirm = input.next();

循环的工作方式是，如果“n”或“N”，它会再次调用构造函数 public Player(String cName, int cStamina, int cDefense, int cStrength, int cAgility, int cIntellect)但是，因为这两个是 String 数据类型，并且构造函数首先调用名称，所以它要么将“n”或“N”识别为名称，要么完全跳过整个名称。我该如何解决这个问题？

import java.util.*;
public class RPG 
{
  static Scanner input = new Scanner(System.in);
  private static String confirm; 

  public static void main(String[] args)
  {
    System.out.println("*~~~~~~~~~~~~~~*\n{ ~ Pinnacle ~ }\n*~~~~~~~~~~~~~~*");
    for (int s = 0; s < 1; s++)
    {

    Player me = new Player(Player.getName(), Player.getStam(), Player.getDef(),
    Player.getStr(), Player.getAgi(), Player.getInt()); 

      for (int i = 0; i < 1; i++)
      {       
        System.out.println("*~~~~~~~~~~~~~~*\n"+Player.name +
        "\nStamina: " + Player.stamina +
        "\nDefense: " + Player.defense +
        "\nStrength: " + Player.strength +
        "\nAgility: " + Player.agility +
        "\nIntellect: " + Player.intellect +
        "\n*~~~~~~~~~~~~~~*");
        System.out.println("Confirm Character (Y/N)");
        confirm = input.next();
        if (confirm.equals("Y") || confirm.equals("y"))
          System.out.println("Character Created!");
        else if (confirm.equals("N") || confirm.equals("n"))
          s--;
        else
          i--;  
      }
  }
  }
}

玩家等级如下

import java.util.*;

public class Player extends Characters
{

static Scanner input = new Scanner(System.in);

public Player(String cName, int cStamina, int cDefense, int cStrength, int cAgility, int cIntellect)
{


name = cName;
stamina = cStamina;
defense = cDefense;
strength = cStrength;
agility = cAgility;
intellect = cIntellect;
}
public static String getName()
{
System.out.println("Enter your character's name.");
String n = input.nextLine();
return n;
}
public static int getStam()
{
System.out.println("Enter your character's stamina.");
int s = input.nextInt();
return s;
}
public static int getDef()
{
System.out.println("Enter your character's defense.");
int d = input.nextInt();
return d;
}
public static int getStr()
{
System.out.println("Enter your character's strength.");
int st = input.nextInt();
return st;
}
public static int getAgi()
{
System.out.println("Enter your character's agility.");
int a = input.nextInt();
return a;
}
public static int getInt()
{
System.out.println("Enter your character's intellect.");
int i = input.nextInt();
return i;
}
public static void flee()
{

}

}

以下是示例输出，其中示例名称作为名字输入:

*~~~~~~~~~~~~~~*
{ ~ Pinnacle ~ }
*~~~~~~~~~~~~~~*
Enter your character's name.
Sample Name
Enter your character's stamina.
5
Enter your character's defense.
5
Enter your character's strength.
8
Enter your character's agility.
3
Enter your character's intellect.
2
*~~~~~~~~~~~~~~*
Sample Name
Stamina: 5
Defense: 5
Strength: 8
Agility: 3
Intellect: 2
*~~~~~~~~~~~~~~*
Confirm Character (Y/N)
n
Enter your character's name.
Enter your character's stamina.
2
Enter your character's defense.
3
Enter your character's strength.
6
Enter your character's agility.
4
Enter your character's intellect.
2
*~~~~~~~~~~~~~~*

Stamina: 2
Defense: 3
Strength: 6
Agility: 4
Intellect: 2
*~~~~~~~~~~~~~~*
Confirm Character (Y/N)
y
Character Created!

如您所见，在确认字符(Y/N)后出现问题。

Answer 1

嗯，我找到了解决您问题的方法，但我不确定为什么会出现您的问题。而不是使用 static Scanner input = new Scanner(System.in);在我们的 Player 类中，在您的每次获取中创建一个新的 Scanner*。

这里有一个建议:

public static Player createPlayerFromConsole() {
    Scanner input = new Scanner(System.in);

    System.out.println("Enter your character's name.");
    String name = input.nextLine();

    System.out.println("Enter your character's stamina.");
    int stamina = input.nextInt();

    System.out.println("Enter your character's defense.");
    int defense = input.nextInt();

    System.out.println("Enter your character's strength.");
    int strength = input.nextInt();

    System.out.println("Enter your character's agility.");
    int agility = input.nextInt();

    System.out.println("Enter your character's intellect.");
    int intellect = input.nextInt();

    return new Player(name, stamina, defense, strength, agility, intellect);
}