java - 数组中的异常错误

Question

我的代码旨在接受一个整数数组并返回一个长度为原始数组长度两倍的整数数组，减去 2。

返回的数组的值应介于原始数组中任何给定的两个值之间1/3 和 2/3。

例如输入数组:

{400, 500, 600}

将返回:

{400,433,466,500,533,566,600}

我的代码如下:

public static void main(String[] args){
            System.out.println("Problem 9 tests");
            int[] arr7={300, 400, 500};
            System.out.println(highDef(arr7));
            System.out.println(" ");

public static int[] highDef(int[] original) {
        int[] newarr = new int[original.length*3-2];
        newarr[0]=original[0];
        int count=0;
        while (count!=newarr.length) {
                int increment=(original[count+1]-original[count])/3;
                newarr[count+1]=original[count]+increment;
                newarr[count+2]=original[count]+(count*increment);
                count+=1;
        }
        return newarr;

Answer 1

第一次看起来不够好:)给你:

public static void main(String[] args) {
    System.out.println("Problem 9 tests");
    int[] arr7 = {300, 400, 500};
    System.out.println(Arrays.toString(highDef(arr7)));
    System.out.println(" ");
}

public static int[] highDef(int[] original) {
    int[] newarr = new int[original.length * 3 - 2];
    newarr[original.length * 3 - 3] = original[original.length-1];

    for(int i=0; i<original.length-1; i++){
        newarr[i*3] = original[i];
        int increment = (original[i+1] - original[i])/3;
        newarr[i*3+1] = original[i] + increment;
        newarr[i*3+2] = original[i] + increment*2;
    }

    return newarr;
}