gpt4 book ai didi

java - 在 JgraphX 中旋转边缘标签

转载 作者:行者123 更新时间:2023-11-30 07:32:21 28 4
gpt4 key购买 nike

我有一条垂直的边缘,我想相应地旋转边缘标签。

例如,将“helloworld.java”绘图部分替换为:

try
{
Object v1 = graph.insertVertex(parent, "1", "TopLeft",
20, 20, 80, 80);
Object v3 = graph.insertVertex(parent, "2", "BottomLeft",
20, 240, 80, 80);
Object e1 = graph.insertEdge(parent, null, "edgelabel",
v1, v3, "dashed=true;endArrow=none;rotation=0");
}

设置rotation=90会旋转边缘,但不会旋转标签。我找到了 mxCurveLabelShape,但我不明白如何使用它。我尝试了一些,但 edge-mxCell 不包含 mxCurve。我尝试过:

 List<mxPoint> pl = ((mxCell)e1).getGeometry().getPoints();
mxCellState ecs1 = new mxCellState(graph.getView(),e1,null);
mxCurveLabelShape cls = new mxCurveLabelShape(ecs1,(mxCurve)pl);

这显然无法工作,因为边缘 mxCell 也不包含非空 mxPoints。我可以使用边缘与其末端相连的位置吗?有没有办法只处理标签并使用旋转来实现?

有什么想法吗?

最佳答案

好吧,我已经弄清楚了,它不太漂亮,而且(还)不适用于正交边缘,即由水平和垂直线段组成的边缘。

我可以让它工作的方法是覆盖一个并为 mxGraphComponent 引入一个函数。也就是说,drawLabel 函数现在检查标签是否来自边缘,如果是,则选择不同的 createTemporaryGraphics 函数。在后者中,边缘框以及标签是已知的,并且在给定边缘框的情况下计算旋转。有一个 boolean 值传递(象限),它告诉边缘是否在矩形的东北和西南之间(quadrant = true),或者在西北和东南之间( >象限=假)。目前,这在位置意义上并不是最佳的(即,垂直标签可能在边缘顶部结束)。但我把调整留给任何想使用它的人;)

开始吧:(将其放置在启动 graphComponent 的任何位置)

mxGraphComponent graphComponent = new mxGraphComponent(graph){
public mxInteractiveCanvas createCanvas()
{
return new mxInteractiveCanvas(){
@Override
public Object drawLabel(String text, mxCellState state, boolean html)
{
Map<String, Object> style = state.getStyle();
mxIShape shapeL = getShape(style);
mxITextShape shape = getTextShape(style, html);
if (g != null && shape != null && drawLabels && text != null
&& text.length() > 0)
{
// Creates a temporary graphics instance for drawing this shape
float opacity = mxUtils.getFloat(style,
mxConstants.STYLE_TEXT_OPACITY, 100);
Graphics2D previousGraphics = g;
if(((mxCell) state.getCell()).isVertex()){
g = createTemporaryGraphics(style, opacity, null);
}else{
//quadrant will be true if the edge is NE or SW
Object target = ((mxCell) state.getCell()).getTarget();
Object source = ((mxCell) state.getCell()).getSource();
boolean quadrant = false;
if(((mxCell)target).getGeometry().getCenterX()<((mxCell)source).getGeometry().getCenterX()){
if(((mxCell)target).getGeometry().getCenterY()>((mxCell)source).getGeometry().getCenterY()){
quadrant = true;
}
}
if(((mxCell)target).getGeometry().getCenterX()>((mxCell)source).getGeometry().getCenterX()){
if(((mxCell)target).getGeometry().getCenterY()<((mxCell)source).getGeometry().getCenterY()){
quadrant = true;
}
}
g = createTemporaryGraphics(style, opacity, state, state.getLabelBounds(),quadrant);
}

// Draws the label background and border
Color bg = mxUtils.getColor(style,
mxConstants.STYLE_LABEL_BACKGROUNDCOLOR);
Color border = mxUtils.getColor(style,
mxConstants.STYLE_LABEL_BORDERCOLOR);
paintRectangle(state.getLabelBounds().getRectangle(), bg, border);

// Paints the label and restores the graphics object
shape.paintShape(this, text, state, style);
g.dispose();
g = previousGraphics;
}

return shape;
}
public Graphics2D createTemporaryGraphics(Map<String, Object> style,
float opacity, mxRectangle bounds, mxRectangle labelbounds, boolean quad)
{
Graphics2D temporaryGraphics = (Graphics2D) g.create();

// Applies the default translate
temporaryGraphics.translate(translate.x, translate.y);

// setup the rotation for the label
double angle = java.lang.Math.atan(bounds.getHeight()/bounds.getWidth());
double rotation = Math.toDegrees(angle);
if(quad){
rotation = - rotation;
}
//get the translation needed
double diff = labelbounds.getHeight()*(1-Math.cos(angle));
double plusy = diff * Math.sin(angle);
double plusx = diff * Math.cos(angle);
// Applies the rotation and translation on the graphics object
if (bounds != null)
{
if (rotation != 0)
{
temporaryGraphics.rotate(Math.toRadians(rotation),
labelbounds.getCenterX(), labelbounds.getCenterY());
temporaryGraphics.translate(
- plusx, plusy);
}
}

// Applies the opacity to the graphics object
if (opacity != 100)
{
temporaryGraphics.setComposite(AlphaComposite.getInstance(
AlphaComposite.SRC_OVER, opacity / 100));
}

return temporaryGraphics;
}
};
}

};

关于java - 在 JgraphX 中旋转边缘标签,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/35917090/

28 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com