java - Xalan+ XSLT+ Java

Question

我的xsl文件

<xsl:stylesheet version="1.0"

xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:good="xalan://com.epam.laba.model.Good"
xmlns:validator="xalan://com.epam.laba.validator.ValidatorXslGood">

    <xsl:include href="parameter.xsl"/>
    <xsl:param name="validator"/>
    <xsl:param name="good"/>

    <xsl:output method="xml" indent="yes"/>

    <xsl:template match="/|node()|@*">
        <xsl:if test="validator:validateGood($good)">
            <xsl:copy>
                <xsl:apply-templates
                select="node()|@*" />
            </xsl:copy>
        </xsl:if>
    </xsl:template>

……

创建 validator 并设置为 xsl 的 Java 代码

    Good good=fillGood(parameters); 
    ValidatorXslGood validatorXslGood=new ValidatorXslGood();
    Source sourceXSL = new StreamSource(xsltFile);
    Transformer transformer = factory.newTransformer(sourceXSL);
    transformer.setParameter(SUBCATEGORY_ID_VALUE, subcategoryId);
    transformer.setParameter(GOOD, good);
    transformer.setParameter(VALIDATOR, validatorXslGood);

    transformer.transform(xmlSource, new StreamResult(outWriter));

但是

The first argument to the non-static Java function 'validateGood' is not a valid object reference. Cannot convert data-type 'void' to 'boolean'.

你能解释一下哪里错了吗？

更新:

ValidatorXslGood.java代码:

public class ValidatorXslGood {

private Good good;

private Map<String, String> setErrors;
private ResourceBundleManager errorManager;

public ValidatorXslGood() {
    errorManager = new ResourceBundleManager();
    errorManager.setResourceBundle(RESOURCE_BUNDLE__FOR_ERROR_FILE);
}

public Good getGood() {
    return good;
}

public void setGood(Good good) {
    this.good = good;
}

public boolean validateGood(Good good) {
    if (checkingName(good.getName())) {
        return true;
    } else {
        return false;
    }
}

---

我尝试在 XSL 中创建 validator

xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:good="xalan://com.epam.laba.model.Good"
xmlns:validator="xalan://com.epam.laba.validator.ValidatorXslGood"
    extension-element-prefixes="validator" >

    <xsl:include href="parameter.xsl"/>
    <xsl:variable name="validatorConstructor" select="validator:new()"/>
    <xsl:param name="validator"/>
    <xsl:param name="good"/>

........

但是我有新的错误，我无法理解路径中的错误

Cannot find class 'com.epam.laba.validator.ValidatorXslGood'. Cannot find external constructor 'com.epam.laba.validator.ValidatorXslGood'.

Answer 1

看起来你错过了语法。 Here声明语法应为prefix:methodName(object, args)，其中prefix 是扩展命名空间前缀(您需要将其声明为xmlns: prefix="URI"extension-element-prefixes="prefix ...") 和 methodName 是在object 上调用的实例方法的名称args 参数。

<xsl:stylesheet
     xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
     xmlns:validator="xalan://com.epam.laba.parser.validator.ValidatorXslGood"
     extension-element-prefixes="validator" ... >

<xsl:param name="validator"/> <!-- That is in reality validatorObject -->
<xsl:param name="good"/>

<xsl:output method="xml" indent="yes"/>

<xsl:template match="/|node()|@*">
    <xsl:if test="validator:validateGood($validator, $good)">
...