java - 在每个线程之间分配数字范围

Question

配置文件

ThreadSize = 10
StartRange = 1
EndRange = 1000

我上面有一个配置文件，其中我有我想使用的线程数，客户端实例能够使用从 1 到 1000 的 ID 范围，假设客户端线程设置为 10，所以每个线程都有范围100 个 id(基本上是通过将结束范围除以线程大小)，它可以在不踩到其他线程的情况下使用。所以我想要的是每个线程都应该使用该范围内的 100 个 id 而不会踩到其他线程 - 例如

Thread1 will use 1 to 100 (id's)
// generate a random number between 1 to 100 and keep on printing values until it has generated all the random values between 1 to 100
Thread2 will use 101 to 200 (id's)
// generate a random number between 101 to 200 and keep on printing values until it has generated all the random values between 101 to 200
Thread3 will use 201 to 300 (id's)
// generate a random number between 201 to 300 and keep on printing values until it has generated all the random values between 201 to 300

-----
----
Thread10 will use 901 to 1000
// generate a random number between 901 to 1000 and keep on printing values until it has generated all the random values between 901 to 1000

我知道如何编写多线程程序，但不确定如何划分各个线程之间的范围。

public static void main(String[] args) {

    for (int i = 1; i <= threadSize; i++) {
        new Thread(new ThreadTask(i)).start();
    }
}


class ThreadTask implements Runnable {
    private int id;

    public ThreadTask(int id) {
    this.id = id;
    }

    public synchronized void run() {

    }
}

Answer 1

每个线程都得到 N = (EndRange - StartRange + 1)/ThreadSize 数字。

线程号 i 获取范围 (StartRange + i*N) - (StartRange + i*N + N - 1)。

在您的示例中 N = (1000 - 1 + 1)/10 = 100。

线程 i = 0 将得到范围 (1 + 0*100) - (1 + 0*100 + 100 - 1) = 1 - 100

线程 i = 1 将得到范围 (1 + 1*100) - (1 + 1*100 + 100 - 1) = 101 - 200

...