java - 每次添加东西时尝试取平均值

Question

package gradeAvg;
import java.util.Scanner;
//Grade Average calculater
public class GradeAvg {

    public static void main(String[] args) {
        // TODO Auto-generated method stub
        Scanner input = new Scanner(System.in);
        System.out.print("Please Enter the first grade being added to the average:");
        double average = input.nextInt();
        System.out.print("The average is now: " + average + " Please enter the second grade being averaged:");
        average += input.nextInt() ;
        System.out.print("The average is now: " + average + " Please enter the third grade being averaged:");
        average += input.nextInt() / 2;
        System.out.print("The average is now: " + average + " Please enter the fourth grade being averaged:");
        average += input.nextInt() / 2;
        System.out.print("The average is now: " + average + " Please enter the fifth grade being averaged:");
        average += input.nextInt() / 2;
        input.close();
        System.out.print(average);




    }

}

嘿伙计们，我对java真的很陌生，数学也很糟糕，我应该制作一个程序，允许用户输入一个值，将其平均，打印出来，然后允许输入另一个值，对其进行平均，然后打印，然后继续。当我在每个输入的末尾除以 2 时，我会出错吗？

Answer 1

平均值是所有数字的总和除以总和中的数字数量。

你在这里所做的事情并不平均。您将每个新数字的一半添加到总和中。我不明白你在这里做什么。

为了让事情更容易理解，让我们做一个和和一个计数器:

public class GradeAvg {

    public static void main(String[] args) {
        int sum;
        int counter;
        // ...
    }

}

每次您请求一个数字时，都会递增计数器并将新数字添加到sum中:

int newNumber;
// ask for input
newNumber = input.nextInt()
sum += newNumber;
counter++;

然后您可以像这样输出平均值:

System.out.println("The average is: " + (double)sum / counter);