Java 程序，它告诉从 1 美分到 99 美分的任何数量的零钱都应该给出什么硬币

Question

我必须编写一个 Java 程序来告诉从 1 美分到 99 美分的任何数量的零钱都应该分发什么硬币。例如，如果金额为 86 美分，则输出将类似于以下内容:

86 cents can be given as 3 quarters, 1 dime and 1 penny.

使用面额为 25、10、5 和 1 的硬币。您的程序将使用以下方法(以及其他方法):

public static int computeCoin(int coinValue,);
// Precondition: 0 < coinValue < 100; 
// Postcondition: returned value has been set equal to the maximum 
//number of coins of the denomination coinValue cents that can be 
//obtained from amount (a different variable) cents. amount has been 
//decreased by the value of the coins, that is, decreased by     
//returnedValue*coinValue.

到目前为止，这就是我所拥有的，但我想我还缺少更多，有人可以帮助我吗？而且我也不应该使用 double 而不是整数。

public class Assignment6{
   public static void main(String [] args){
   amount = (int)(Double.parseDouble(args[0])*100);

   System.out.println("Five: " + computeCoin(500));
   System.out.println("one: " + computeCoin(100) );
   System.out.println("Q : " + computeCoin(25) );
   System.out.println("D : " + computeCoin(10) );
   System.out.println("N : " + computeCoin(5) );
   System.out.println("P : " + computeCoin(1) );
}

Answer 1

public class Assignment6 {
    private static int amount = 0;
    public static void main(String[] args) {
        amount = (int)(Double.parseDouble(args[0])*100);
        System.out.println("Five: " + computeCoin(500));
        System.out.println("one: " + computeCoin(100) );
        System.out.println("Q : " + computeCoin(25) );
        System.out.println("D : " + computeCoin(10) );
        System.out.println("N : " + computeCoin(5) );
        System.out.println("P : " + computeCoin(1) );
    }

    public static int computeCoin(int cointValue) {
        int val = amount / cointValue;
        amount -= val * cointValue;
        return val;
    }
}

这里的技巧在于 computeCoin 方法，事实上除法是整数除法，所以 val 将保留 ' maximum' 给定值 (coinValue) 的硬币数量，其总值不超过 amount。