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java - 使用 JAXB 创建具有属性和动态值的 XML

转载 作者:行者123 更新时间:2023-11-30 07:22:39 24 4
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我想使用 JAXB 创建 XML。它应该有属性,其值必须来自相应类中定义的属性。

当前的输出是将属性作为子标签,而不是作为主标签中的属性。

我想要的 XML 结构如下。

<?xml version="1.0" encoding="UTF-8"?>
<company>
<department name="hr">
<branch name="hr-recruitment">
<manager> Manasa </manager>
<phone>992222222</phone>
<salary> 20000 </salary>
</branch>
<branch name="hr-finance">
<manager> Sunder </manager>
<phone>993333332</phone>
<salary> 50000 </salary>
</branch>
</department>
<department name="transport">
<branch name="transport-employee">
<manager> Raman </manager>
<phone>888888888</phone>
<salary> 30000 </salary>
</branch>
<branch name="transport-goods">
<manager> Sheela </manager>
<phone>99999999</phone>
<salary> 75000 </salary>
</branch>
</department>
</company>

这是标有 JAXB 注释的 3 个类:

1) 公司类

@XmlRootElement(name = "tarang")
public class Company {

private List<Department> listDepartments;

public Company(List<Department> listDepartments) {
this.listDepartments = listDepartments;
}

public Company() {

}

@XmlElementRef
public List<Department> getListDepartments() {
return listDepartments;
}

public void setListDepartments(ArrayList<Department> listDepartments) {
this.listDepartments = listDepartments;
}

}

2) Department.class

@XmlRootElement(name = "department")
public class Department {

private String strDepartmentName;

private List<Branch> listBranchs;

public Department(String strDepartmentName, List<Branch> listBranchs) {
this.strDepartmentName = strDepartmentName;
this.listBranchs = listBranchs;
}

public Department() {

}

@XmlElement(name = "name")
public String getStrDepartmentName() {
return strDepartmentName;
}

public void setStrDepartmentName(String strDepartmentName) {
this.strDepartmentName = strDepartmentName;
}

@XmlElementRef
public List<Branch> getListBranchs() {
return listBranchs;
}

public void setListBranchs(List<Branch> listBranchs) {
this.listBranchs = listBranchs;
}

}

3) 分支类

@XmlRootElement(name = "branch")
public class Branch {

private String strName;
private String strManagerName;
private String strPhone;
private int intSalary;

public Branch(String strName, String strManagerName, String strPhone,
int intSalary) {
this.strName = strName;
this.strManagerName = strManagerName;
this.strPhone = strPhone;
this.intSalary = intSalary;
}

public Branch() {
// TODO Auto-generated constructor stub
}

@XmlElement(name = "name")
public String getStrName() {
return strName;
}

public void setStrName(String strName) {
this.strName = strName;
}

@XmlElement(name = "manager")
public String getStrManagerName() {
return strManagerName;
}

public void setStrManagerName(String strManagerName) {
this.strManagerName = strManagerName;
}

@XmlElement(name = "phone")
public String getStrPhone() {
return strPhone;
}

public void setStrPhone(String strPhone) {
this.strPhone = strPhone;
}

@XmlElement(name = "salary")
public int getIntSalary() {
return intSalary;
}

public void setIntSalary(int intSalary) {
this.intSalary = intSalary;
}

}

我当前的设计包含 3 个类。

1)公司2)部门3)分公司

关系是:

1) class Company -has a- List of Departments.
2) class Department -has a- name (String).
3) class Department -has a- List of Branches.
4) class Branch -has a- name (String)
5) class Branch -has a- manager (String)
6) class Branch -has a- phone (String)
7) class Branch -has a- salary (String)

当前的输出是:

 <?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<tarang>
<department>
<branch>
<salary>50000</salary>
<manager>Manasa</manager>
<name>hr-recruitment</name>
<phone>999999999</phone>
</branch>
<branch>
<salary>40000</salary>
<manager>Sundar</manager>
<name>hr-finance</name>
<phone>888888888</phone>
</branch>
<name>hr</name>
</department>
<department>
<branch>
<salary>30000</salary>
<manager>Raman</manager>
<name>transport-employee</name>
<phone>7777777777</phone>
</branch>
<branch>
<salary>20000</salary>
<manager>Sheela</manager>
<name>transport-goods</name>
<phone>6666666666</phone>
</branch>
<name>tranport</name>
</department>
</tarang>

部门名称和分支名称未作为属性附加。请建议我在类中进行更正,其中必须应用 @xmlattribute 注释才能获得所需的输出。

最佳答案

@XmlAttribute 应该添加到您的 Department 类中的字段声明中:

@XmlAttribute(name = "name")
private String strDepartmentName;

参见 here有关 XmlAttribute 注释的更多详细信息。

关于java - 使用 JAXB 创建具有属性和动态值的 XML,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/12525765/

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