java - Spring Boot - 事务管理不起作用

Question

期望 - 延迟加载不应在事务范围之外工作(例如在其余 Controller 中)，但它可以工作。

问题出在@Transactional中，在我的配置中Spring应用程序没有使用它。我该如何修复它？

...Rest Controller 没有任何事务方法，它仅使用指定的服务来加载实体。如果未在服务中加载，则依赖集合应为空。

应用程序入门类:

@SpringBootApplication
@EntityScan("com.vl.pmanager.domain.model")
@EnableJpaRepositories("com.vl.pmanager.domain.repository")
@EnableTransactionManagement
public class ProjectManagerApplication {

    public static void main(String[] args) {
        SpringApplication.run(ProjectManagerApplication.class, args);
    }
}

我知道 spring boot 自动配置存储库并扫描实体，但我希望添加...

@EntityScan("com.vl.pmanager.domain.model")
@EnableJpaRepositories("com.vl.pmanager.domain.repository")

我还尝试将@Transactional添加到存储库界面，但它对我不起作用

package com.vl.pmanager.domain.repository;

import com.vl.pmanager.domain.model.Tag;
import org.springframework.data.repository.PagingAndSortingRepository;
import org.springframework.stereotype.Repository;
import org.springframework.transaction.annotation.Transactional;

@Repository
@Transactional
public interface TagRepository extends PagingAndSortingRepository<Tag, Long> {
}

所以我从存储库中删除了@Transactional，创建了其他服务层来使用注释对其进行管理并将服务注入(inject)到 Controller :

package com.vl.pmanager.domain.db.service.api;

import com.vl.pmanager.domain.model.Tag;
import org.springframework.data.domain.Page;
import org.springframework.data.domain.Pageable;

public interface ITagManager {
    Page<Tag> findAll(Pageable pageable);
    Tag findOne(Long id);
}
// ======================== TAG SERVICE WRAPPED WITH TRANSACTION ==========================
package com.vl.pmanager.domain.db.service;

import com.vl.pmanager.domain.db.service.api.ITagManager;
import com.vl.pmanager.domain.model.Tag;
import com.vl.pmanager.domain.repository.TagRepository;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.data.domain.Page;
import org.springframework.data.domain.Pageable;
import org.springframework.stereotype.Service;
import org.springframework.transaction.annotation.Transactional;

@Service
@Transactional
public class TagManager implements ITagManager {
    @Autowired
    private TagRepository tagRepository;

    @Override
    public Page<Tag> findAll(Pageable pageable) {
        return tagRepository.findAll(pageable);
    }

    @Override
    public Tag findOne(Long id) {
        return tagRepository.findOne(id);
    }
}
// ====================== REST CONTROLLER ============================
package com.vl.pmanager.web;

import com.vl.pmanager.domain.db.service.api.ITagManager;
import com.vl.pmanager.domain.model.Tag;
import org.slf4j.Logger;
import org.slf4j.LoggerFactory;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.data.domain.Page;
import org.springframework.data.domain.Pageable;
import org.springframework.data.web.PageableDefault;
import org.springframework.http.MediaType;
import org.springframework.web.bind.annotation.PathVariable;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.bind.annotation.RestController;

@RestController
@RequestMapping(value = "/tags")
public class TagController {
    private static final int DEFAULT_PAGE_SIZE = 50;

    @Autowired
    private ITagManager tagManager;

    @RequestMapping(method = RequestMethod.GET, consumes = MediaType.ALL_VALUE)
    public Page<Tag> getTags(@PageableDefault(size = DEFAULT_PAGE_SIZE) Pageable pageable) {
        return tagManager.findAll(pageable);
    }

    @RequestMapping(value = "/{id}", method = RequestMethod.GET, consumes = MediaType.ALL_VALUE)
    public Tag getTag(@PathVariable("id") Long id) {
        return tagManager.findOne(id);
    }
}

Tag 实体有一个字段 Set projectInfo 映射到具有 @ManyToMany 关系的其他实体，且 FetchType fetch() 默认 LAZY； 因此返回结果不能包含依赖实体，但它确实包含。

我还监控了数据库日志:

// make request - load data using db service to controller level
Hibernate: select count(tag0_.id) as col_0_0_ from tag tag0_
Hibernate: select tag0_.id as id1_6_, tag0_.description as descript2_6_, tag0_.name as name3_6_ from tag tag0_ limit ?
// converting data to JSON automatically
Hibernate: select projectinf0_.tags as tags1_6_0_, projectinf0_.project_info as project_2_7_0_, projectinf1_.id as id1_4_1_, projectinf1_.description as descript2_4_1_, projectinf1_.name as name3_4_1_ from tag_project_info projectinf0_ inner join project_info projectinf1_ on projectinf0_.project_info=projectinf1_.id where projectinf0_.tags=?
Hibernate: select projectinf0_.tags as tags1_6_0_, projectinf0_.project_info as project_2_7_0_, projectinf1_.id as id1_4_1_, projectinf1_.description as descript2_4_1_, projectinf1_.name as name3_4_1_ from tag_project_info projectinf0_ inner join project_info projectinf1_ on projectinf0_.project_info=projectinf1_.id where projectinf0_.tags=?
Hibernate: select projectinf0_.tags as tags1_6_0_, projectinf0_.project_info as project_2_7_0_, projectinf1_.id as id1_4_1_, projectinf1_.description as descript2_4_1_, projectinf1_.name as name3_4_1_ from tag_project_info projectinf0_ inner join project_info projectinf1_ on projectinf0_.project_info=projectinf1_.id where projectinf0_.tags=?
Hibernate: select projectinf0_.tags as tags1_6_0_, projectinf0_.project_info as project_2_7_0_, projectinf1_.id as id1_4_1_, projectinf1_.description as descript2_4_1_, projectinf1_.name as name3_4_1_ from tag_project_info projectinf0_ inner join project_info projectinf1_ on projectinf0_.project_info=projectinf1_.id where projectinf0_.tags=?
Hibernate: select projectinf0_.tags as tags1_6_0_, projectinf0_.project_info as project_2_7_0_, projectinf1_.id as id1_4_1_, projectinf1_.description as descript2_4_1_, projectinf1_.name as name3_4_1_ from tag_project_info projectinf0_ inner join project_info projectinf1_ on projectinf0_.project_info=projectinf1_.id where projectinf0_.tags=?

我知道只有 5 个额外请求，因为我只有 5 个依赖于 tag project_info。因此，作为结论，我的交易级别不管理交易。...我已经检查了注入(inject)bean的数据源和transactionManager - 已创建。启动时或运行时没有错误、没有警告...

Answer 1

@JBNizet

这不是交易问题。在文档中查找属性 spring.jpa.open-in-view ，如果不需要则将其设置为 false

我已添加此答案以将问题标记为已关闭。如果我关闭jpa open in view，事务就会像我预期的那样工作。

对于版主请将作者答案更改为@JBNizet