javascript - 密码战 : Grasshopper - Grade book challenge

Question

这是解决方案就在我面前，但我似乎找不到的时候之一!所以请耐心等待我。 kata instruction是以下内容:

Complete the function so that it finds the mean of the three scores passed to it and returns the letter value associated with that grade.

Numerical Score       Letter Grade

90 <= score <= 100    'A'
80 <= score < 90      'B'
70 <= score < 80      'C'
60 <= score < 70      'D'
0 <= score < 60       'F'

Tested values are all between 0 and 100. There is no need to check for negative values or values greater than 100.

这是我的解决方案:

function getGrade (s1, s2, s3) {
  var score = (s1 + s2 + s3) / 3;
  if (90 <= score && score >= 100) {
      return 'A';
  } else if (80 <= score && score > 90) {
    return 'B';
  } else if (70 <= score && score > 80) {
    return 'C';
  } else if (60 <= score && score > 70) {
    return 'D';
  } else if (0 <= score && score > 60) {
    return 'F';
  }
}

getGrade(5,40,93);
getGrade(30,85,96);
getGrade(92,70,40);

我这辈子都弄不明白我做错了什么。

Answer 1

你在 if 语句中的条件都是错误的。这些是合适的条件

function getGrade (s1, s2, s3) {
  var score = (s1 + s2 + s3) / 3;
  if (score >= 90 && score <= 100) {
      return 'A';
  } else if (score >= 80 && score < 90) {
    return 'B';
  } else if (score >= 70&& score < 80) {
    return 'C';
  } else if (score >= 60  && score < 70) {
    return 'D';
  } else {
    return 'F';
  }
}