java - 从字符串中删除字母数字词

Question

我正在尝试从字符串中删除字母数字单词..

 String[] sentenceArray= {"India123156 hel12lo 10000 cricket 21355 sport news 000Fifa"};
    for(String s: sentenceArray)
        {
            String finalResult = new String();
            String finalResult1 = new String();
            String str= s.toString();
            System.out.println("before regex : "+str);
            String regex = "(\\d?[,/%]?\\d|^[a-zA-Z0-9_]*)";
            finalResult1 = str.replaceAll(regex, " ");
            finalResult = finalResult1.trim().replaceAll(" +", " ");
            System.out.println("after regex : "+finalResult);
        }

输出:hello cricket sport news Fifa

但我需要的输出是:板球运动新闻

请各位大侠帮忙提前谢谢你

Answer 1

要匹配您要排除的单词和后面的空格字符，您可以在不区分大小写的模式下使用以下正则表达式 (demo):

\b(?=[a-z]*\d+)\w+\s*\b

在 Java 中，要替换它，您可以这样做:

String replaced = your_original_string.replaceAll("(?i)\\b(?=[a-z]*\\d+[a-z]*)\\w+\\s*\\b", "");

逐个 token 的解释

\b                       # the boundary between a word char (\w) and
                         # something that is not a word char
(?=                      # look ahead to see if there is:
  [a-z]*                 #   any character of: 'a' to 'z' (0 or more
                         #   times (matching the most amount
                         #   possible))
  \d+                    #   digits (0-9) (1 or more times (matching
                         #   the most amount possible))
)                        # end of look-ahead
\w+                      # word characters (a-z, A-Z, 0-9, _) (1 or
                         # more times (matching the most amount
                         # possible))
\s*                      # whitespace (\n, \r, \t, \f, and " ") (0 or
                         # more times (matching the most amount
                         # possible))
\b                       # the boundary between a word char (\w) and
                         # something that is not a word char