java - 序数指示符的后缀

Question

对于提供数字后缀有什么建议吗？

我正在努力为我的代码提供以下输出:

示例

输入一个整数(1-46):6斐波那契数列中的第 6 个数字是:8

以下是我迄今为止完成的工作:

import java.util.*;

public class Somethingpart2 {

    public static void main(String[] args) {

        Scanner kbd = new Scanner(System.in);

        //Variable Declaration 
        int number;
        long Fibnumber;


        Boolean accepted, limit;

        //Beginning of user input for the Fibonacci sequence 
        System.out.print("Enter an integer (1-46): ");
        number = kbd.nextInt();

        Fibnumber = Math.round(Math.pow((1+Math.sqrt(5))/2, number) / Math.sqrt(5)); 
        accepted = number >= 1 && number <= 46;
        limit = number == Fibnumber;


        if (accepted) {
            do {
                System.out.println("The " + number +" number in the Fibonacci sequence is: "+Fibnumber);
                //if ())
                return;
            }
            while (limit);
        }
        else
            System.out.println("Not a valid number.");

我在想 //if () 位于哪里，我可以想出一种使用 .contains 或 indexOf 的方法> 例如，如果变量 number 的最后一位数字为 3，则在 3 后面应用“rd”。

*****已更新*****我似乎遇到的最后一个问题是异常编号:11、12 和 13。

如何确保 11、12 和 13 在下面的 if 语句中被忽略:

public static void main(String[] args) {

    Scanner kbd = new Scanner(System.in);

    //Variable Declaration 
    int number;
    long Fibnumber;


    Boolean accepted, limit;

    //Beginning of user input for the Fibonacci sequence 
    System.out.print("Enter an integer (1-46): ");
    number = kbd.nextInt();

    Fibnumber = Math.round(Math.pow((1+Math.sqrt(5))/2, number) / Math.sqrt(5)); 
    accepted = number >= 1 && number <= 46;
    limit = number == Fibnumber;


    if (accepted) {
        do {
            //System.out.println("The " + number +" number in the Fibonacci sequence is: "+Fibnumber);
            if (number % 10 == 3 && number % 10 !=13)
                System.out.println("The "+ number+"rd number in the Fibonacci sequence is: "+ Fibnumber);
            else
                if (number % 10 == 2 && number % 10 != 12)
                    System.out.println("The "+ number+ "nd number in the Fibonacci sequence is: " +Fibnumber);
                else
                    if (number % 10 == 1 && number % 10 != 11)
                        System.out.println("The "+ number+ "st number in the Fibonacci sequence is: " +Fibnumber);
                    else
                        System.out.println("The "+ number+ "th number in the Fibonacci sequence is: " +Fibnumber);
            return;
        }
        while (limit);
    }
    else
        System.out.println("Not a valid number.");

我以为我正在以正确的方式处理这件事。是我把括号弄乱了吗？我刚刚尝试了不同的组合但没有成功。

Answer 1

这是我想到的:

public static void main(String[] args) {

    Scanner kbd = new Scanner(System.in);

    //Variable Declaration 
    int number;
    long Fibnumber;


    Boolean accepted, limit;

    //Beginning of user input for the Fibonacci sequence 
    System.out.print("Enter an integer (1-46): ");
    number = kbd.nextInt();

    System.out.println("");//Provides a space between the two print out statements within the program. 

    Fibnumber = Math.round(Math.pow((1+Math.sqrt(5))/2, number) / Math.sqrt(5)); 
    accepted = number >= 1 && number <= 46;
    limit = number == Fibnumber;


    if (accepted) {
        do {
            if (number % 10 == 3 && number !=13)
                System.out.println("The "+ number+"rd number in the Fibonacci sequence is: "+ Fibnumber);
            else
                if (number % 10 == 2 && number != 12)
                    System.out.println("The "+ number+ "nd number in the Fibonacci sequence is: " +Fibnumber);
                else
                    if (number % 10 == 1 && number != 11)
                        System.out.println("The "+ number+ "st number in the Fibonacci sequence is: " +Fibnumber);
                    else
                        System.out.println("The "+ number+ "th number in the Fibonacci sequence is: " +Fibnumber);
            return;
        }
        while (limit);
    }
    else
        System.out.println("Not a valid number.");