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java - 如何使用 java.time.ZonedDateTime 在 UTC 中生成原始长值

转载 作者:行者123 更新时间:2023-11-30 07:00:47 24 4
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什么是一种相当有效但最重要的是一种将 UTC 时间戳生成为 long 值(java 原始类型)的干净简洁的方法。

我只需要它精确到最精确的毫秒值。

我更愿意使用 java.time.ZonedDateTime,因为它是一种获取 UTC 时间戳的简洁方法,并且不需要任何我不想使用的外部日期库,例如 Joda 或 Apache。

组成原始 long 值的 19 位数字将被分解(格式化)如下,并举例说明:

2015  - 4 digit year with range 1000 - 9223. 
- no zero padding allowed to ensure length is always
a 19 digit long value
- 1000 is the minimum value of a four digit year
- 9223 is the maximum value based on first four digits
of Long.MAX_VALUE or 9223372036854775807

01 - 2 digit month with range 01 - 12
- zero padded to ensure 2 digits always
- jan is 01 and dec is 12

20 - 2 digit day with range 01 - 31
- zero padded to ensure 2 digits always

07 - 2 digit hour with range 00 - 23
- zero padded to ensure 2 digits always
- uses a 24 hour clock
- 00 is 12 AM while 23 is 11 PM

00 - 2 digit minute with range 00 - 59
- zero padded to ensure 2 digits always

00 - 2 digit second with range 00 - 59
- zero padded to ensure 2 digits always

999 - 3 digit milliseconds with range 000 - 999
- zero padded to ensure 3 digits always

99 - only 2 digits left over from primitive long. Ignore these as they
will be used internally as specialized counters within my program

我的出发点是使用以下内容:

ZonedDateTime value = ZonedDateTime.now( ZoneOffset.UTC );

最佳答案

ZonedDateTime value = ZonedDateTime.now(ZoneOffset.UTC);
System.out.println(value.get(ChronoField.NANO_OF_SECOND));

DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyyMMddHHmmssSSS");
long time = Long.parseLong(formatter.format(value)) * 100;
System.out.println(time);

关于java - 如何使用 java.time.ZonedDateTime 在 UTC 中生成原始长值,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/30276226/

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