- html - 出于某种原因,IE8 对我的 Sass 文件中继承的 html5 CSS 不友好?
- JMeter 在响应断言中使用 span 标签的问题
- html - 在 :hover and :active? 上具有不同效果的 CSS 动画
- html - 相对于居中的 html 内容固定的 CSS 重复背景?
我正在尝试转动 this example在 Spring Boot 应用程序中,问题在于 RestfulServer
是一个 servlet,而且我并不是真的试图创建一个单独的应用程序,而是创建一个或多或少扩展该 servlet 的应用程序。我似乎遇到的问题是,我使用 WebApplicationInitializer
和 SpringBootApplicationInitializer
尝试过的事情是,它们在执行其他 @Configuration
之前没有初始化 servlet code> 类。如何将 JpaServerDemo
类转换为 Spring Boot?(注意:我们不需要第二个 servlet)
更新这是我尝试的最后一件事,但是我也尝试了WebApplicationInitializer
的各种迭代,或者在configure
方法中执行操作这看起来很棘手,因为它没有 servletContext
,并且 onStartup
没有 ApplicationContext
@SpringBootApplication
public class Application extends SpringBootServletInitializer {
@Override
public void onStartup( ServletContext servletContext ) throws ServletException {
super.onStartup( servletContext );
RestfulServer server = new RestfulServer();
servletContext.addServlet( "restful", server );
/*
* We want to support FHIR DSTU3 format. This means that the server
* will use the DSTU3 bundle format and other DSTU3 encoding changes.
*
* If you want to use DSTU1 instead, change the following line, and change the 3 occurrences of dstu2 in web.xml to dstu1
*/
server.setFhirContext( FhirContext.forDstu3() );
WebApplicationContext myAppCtx = this.createRootApplicationContext( servletContext );
// Get the spring context from the web container (it's declared in web.xml)
/*
* The BaseJavaConfigDstu3.java class is a spring configuration
* file which is automatically generated as a part of hapi-fhir-jpaserver-base and
* contains bean definitions for a resource provider for each resource type
*/
List<IResourceProvider> beans = myAppCtx.getBean( "myResourceProvidersDstu3", List.class );
server.setResourceProviders( beans );
/*
* The system provider implements non-resource-type methods, such as
* transaction, and global history.
*/
server.setPlainProviders( myAppCtx.getBean( "mySystemProviderDstu3", JpaSystemProviderDstu3.class ) );
/*
* The conformance provider exports the supported resources, search parameters, etc for
* this server. The JPA version adds resource counts to the exported statement, so it
* is a nice addition.
*/
IFhirSystemDao<Bundle, Meta> systemDao = myAppCtx.getBean( "mySystemDaoDstu3", IFhirSystemDao.class );
DaoConfig daoConfig = myAppCtx.getBean( DaoConfig.class );
JpaConformanceProviderDstu3 confProvider = new JpaConformanceProviderDstu3( server, systemDao, daoConfig );
confProvider.setImplementationDescription( "Example Server" );
server.setServerConformanceProvider( confProvider );
/*
* Enable ETag Support (this is already the default)
*/
server.setETagSupport( ETagSupportEnum.ENABLED );
/*
* This server tries to dynamically generate narratives
*/
FhirContext ctx = server.getFhirContext();
ctx.setNarrativeGenerator( new
DefaultThymeleafNarrativeGenerator() );
/*
* Default to JSON and pretty printing
*/
server.setDefaultPrettyPrint( true );
server.setDefaultResponseEncoding( EncodingEnum.JSON );
/*
* -- New in HAPI FHIR 1.5 --
* This configures the server to page search results to and from
* the database, instead of only paging them to memory. This may mean
* a performance hit when performing searches that return lots of results,
* but makes the server much more scalable.
*/
server.setPagingProvider( myAppCtx.getBean( DatabaseBackedPagingProvider.class ) );
/*
* Load interceptors for the server from Spring (these are defined in FhirServerConfig.java)
*/
Collection<IServerInterceptor> interceptorBeans = myAppCtx.getBeansOfType( IServerInterceptor.class ).values();
for (
IServerInterceptor interceptor : interceptorBeans )
{
server.registerInterceptor( interceptor );
}
/*
* If you are hosting this server at a specific DNS name, the server will try to
* figure out the FHIR base URL based on what the web container tells it, but
* this doesn't always work. If you are setting links in your search bundles that
* just refer to "localhost", you might want to use a server address strategy:
*/
//setServerAddressStrategy(new HardcodedServerAddressStrategy("http://example.com/fhir/baseDstu2"));
/*
* If you are using DSTU3+, you may want to add a terminology uploader, which allows
* uploading of external terminologies such as Snomed CT. Note that this uploader
* does not have any security attached (any anonymous user may use it by default)
* so it is a potential security vulnerability. Consider using an AuthorizationInterceptor
* with this feature.
*/
server.registerProvider( myAppCtx.getBean( TerminologyUploaderProviderDstu3.class ) );
}
@Override
protected SpringApplicationBuilder configure( final SpringApplicationBuilder builder ) {
return builder;
}
public static void main( String[] args ) {
configureApplication( new SpringApplicationBuilder() ).run( args );
}
private static SpringApplicationBuilder configureApplication( final SpringApplicationBuilder builder ) {
return builder.sources( Application.class );
}
}
最佳答案
这似乎有效,我将@WebServlet
添加到类中,并使用Spring 4.3的无注释构造函数注入(inject)功能注入(inject)WebApplicationContext
。我还将 @ServletComponentScan
添加到我的 Application
中,它位于同一包中
@WebServlet( "/fhir/*" )
public class FhirServlet extends RestfulServer {
private static final long serialVersionUID = 3341258540126825379L;
private final WebApplicationContext myAppCtx;
public FhirServlet( WebApplicationContext myAppCtx ) {
this.myAppCtx = myAppCtx;
}
@Override
protected void initialize() throws ServletException {
this.setFhirContext( FhirContext.forDstu3() );
this.setServerAddressStrategy( new IncomingRequestAddressStrategy() );
this.setDefaultPrettyPrint( true );
this.setDefaultResponseEncoding( EncodingEnum.JSON );
this.setETagSupport( ETagSupportEnum.ENABLED );
/*
* The BaseJavaConfigDstu3.java class is a spring configuration
* file which is automatically generated as a part of hapi-fhir-jpaserver-base and
* contains bean definitions for a resource provider for each resource type
*/
List<IResourceProvider> beans = myAppCtx.getBean( "myResourceProvidersDstu3", List.class );
setResourceProviders( beans );
/*
* The system provider implements non-resource-type methods, such as
* transaction, and global history.
*/
setPlainProviders( myAppCtx.getBean( "mySystemProviderDstu3", JpaSystemProviderDstu3.class ) );
/*
* The conformance provider exports the supported resources, search parameters, etc for
* this server. The JPA version adds resource counts to the exported statement, so it
* is a nice addition.
*/
IFhirSystemDao<Bundle, Meta> systemDao = myAppCtx.getBean( "mySystemDaoDstu3", IFhirSystemDao.class );
JpaConformanceProviderDstu3 confProvider = new JpaConformanceProviderDstu3( this, systemDao, myAppCtx.getBean( DaoConfig.class ) );
confProvider.setImplementationDescription( "Example Server" );
setServerConformanceProvider( confProvider );
/*
* This server tries to dynamically generate narratives
*/
getFhirContext().setNarrativeGenerator( new DefaultThymeleafNarrativeGenerator() );
/*
* -- New in HAPI FHIR 1.5 --
* This configures the server to page search results to and from
* the database, instead of only paging them to memory. This may mean
* a performance hit when performing searches that return lots of results,
* but makes the server much more scalable.
*/
setPagingProvider( myAppCtx.getBean( DatabaseBackedPagingProvider.class ) );
/*
* Load interceptors for the server from Spring (these are defined in FhirServerConfig.java)
*/
Collection<IServerInterceptor> interceptorBeans = myAppCtx.getBeansOfType( IServerInterceptor.class ).values();
for ( IServerInterceptor interceptor : interceptorBeans ) {
this.registerInterceptor( interceptor );
}
/*
* If you are hosting this server at a specific DNS name, the server will try to
* figure out the FHIR base URL based on what the web container tells it, but
* this doesn't always work. If you are setting links in your search bundles that
* just refer to "localhost", you might want to use a server address strategy:
*/
//setServerAddressStrategy(new HardcodedServerAddressStrategy("http://example.com/fhir/baseDstu2"));
/*
* If you are using DSTU3+, you may want to add a terminology uploader, which allows
* uploading of external terminologies such as Snomed CT. Note that this uploader
* does not have any security attached (any anonymous user may use it by default)
* so it is a potential security vulnerability. Consider using an AuthorizationInterceptor
* with this feature.
*/
registerProvider( myAppCtx.getBean( TerminologyUploaderProviderDstu3.class ) );
}
}
关于java - 如何让我的 Spring Boot 应用程序基于外部 Servlet?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/41033123/
我正在编写一个具有以下签名的 Java 方法。 void Logger(Method method, Object[] args); 如果一个方法(例如 ABC() )调用此方法 Logger,它应该
我是 Java 新手。 我的问题是我的 Java 程序找不到我试图用作的图像文件一个 JButton。 (目前这段代码什么也没做,因为我只是得到了想要的外观第一的)。这是我的主课 代码: packag
好的,今天我在接受采访,我已经编写 Java 代码多年了。采访中说“Java 垃圾收集是一个棘手的问题,我有几个 friend 一直在努力弄清楚。你在这方面做得怎么样?”。她是想骗我吗?还是我的一生都
我的 friend 给了我一个谜语让我解开。它是这样的: There are 100 people. Each one of them, in his turn, does the following
如果我将使用 Java 5 代码的应用程序编译成字节码,生成的 .class 文件是否能够在 Java 1.4 下运行? 如果后者可以工作并且我正在尝试在我的 Java 1.4 应用程序中使用 Jav
有关于why Java doesn't support unsigned types的问题以及一些关于处理无符号类型的问题。我做了一些搜索,似乎 Scala 也不支持无符号数据类型。限制是Java和S
我只是想知道在一个 java 版本中生成的字节码是否可以在其他 java 版本上运行 最佳答案 通常,字节码无需修改即可在 较新 版本的 Java 上运行。它不会在旧版本上运行,除非您使用特殊参数 (
我有一个关于在命令提示符下执行 java 程序的基本问题。 在某些机器上我们需要指定 -cp 。 (类路径)同时执行java程序 (test为java文件名与.class文件存在于同一目录下) jav
我已经阅读 StackOverflow 有一段时间了,现在我才鼓起勇气提出问题。我今年 20 岁,目前在我的家乡(罗马尼亚克卢日-纳波卡)就读 IT 大学。足以介绍:D。 基本上,我有一家提供簿记应用
我有 public JSONObject parseXML(String xml) { JSONObject jsonObject = XML.toJSONObject(xml); r
我已经在 Java 中实现了带有动态类型的简单解释语言。不幸的是我遇到了以下问题。测试时如下代码: def main() { def ks = Map[[1, 2]].keySet()
一直提示输入 1 到 10 的数字 - 结果应将 st、rd、th 和 nd 添加到数字中。编写一个程序,提示用户输入 1 到 10 之间的任意整数,然后以序数形式显示该整数并附加后缀。 public
我有这个 DownloadFile.java 并按预期下载该文件: import java.io.*; import java.net.URL; public class DownloadFile {
我想在 GUI 上添加延迟。我放置了 2 个 for 循环,然后重新绘制了一个标签,但这 2 个 for 循环一个接一个地执行,并且标签被重新绘制到最后一个。 我能做什么? for(int i=0;
我正在对对象 Student 的列表项进行一些测试,但是我更喜欢在 java 类对象中创建硬编码列表,然后从那里提取数据,而不是连接到数据库并在结果集中选择记录。然而,自从我这样做以来已经很长时间了,
我知道对象创建分为三个部分: 声明 实例化 初始化 classA{} classB extends classA{} classA obj = new classB(1,1); 实例化 它必须使用
我有兴趣使用 GPRS 构建车辆跟踪系统。但是,我有一些问题要问以前做过此操作的人: GPRS 是最好的技术吗?人们意识到任何问题吗? 我计划使用 Java/Java EE - 有更好的技术吗? 如果
我可以通过递归方法反转数组,例如:数组={1,2,3,4,5} 数组结果={5,4,3,2,1}但我的结果是相同的数组,我不知道为什么,请帮助我。 public class Recursion { p
有这样的标准方式吗? 包括 Java源代码-测试代码- Ant 或 Maven联合单元持续集成(可能是巡航控制)ClearCase 版本控制工具部署到应用服务器 最后我希望有一个自动构建和集成环境。
我什至不知道这是否可能,我非常怀疑它是否可能,但如果可以,您能告诉我怎么做吗?我只是想知道如何从打印机打印一些文本。 有什么想法吗? 最佳答案 这里有更简单的事情。 import javax.swin
我是一名优秀的程序员,十分优秀!