java - 使用 Java 的 XSLT

Question

我在 stackoverflow 的一篇帖子中发现了以下示例 -

import javax.xml.transform.*;
import javax.xml.transform.stream.StreamResult;
import javax.xml.transform.stream.StreamSource;
import java.io.File;
import java.io.IOException;
import java.net.URISyntaxException;

public class TestMain {
    public static void main(String[] args) throws IOException, URISyntaxException, TransformerException {
        TransformerFactory factory = TransformerFactory.newInstance();
        Source xslt = new StreamSource(new File("transform.xslt"));
        Transformer transformer = factory.newTransformer(xslt);

        Source text = new StreamSource(new File("input.xml"));
        transformer.transform(text, new StreamResult(new File("output.xml")));
    }
}

在上面的示例中，我想使用输入作为字符串，输出作为字符串，并仅从文件中读取 xslt。可以实现这个目标吗？

Answer 1

查看带有 InputStream 的 StreamSource 构造函数 https://docs.oracle.com/javase/7/docs/api/javax/xml/transform/stream/StreamSource.html#StreamSource(java.io.InputStream)

您可以像这样从字符串创建输入:

    InputStream input = new ByteArrayInputStream("<your string input>".getBytes(StandardCharsets.UTF_8));
    Source text = new StreamSource(input);

并使用 StringWriter 和 StreamResult 将输出作为 string:

    StringWriter outputWriter = new StringWriter();
    StreamResult result = new StreamResult( outputWriter );

    transformer.transform( text, result );  

    String outputAsString = outputWriter.getBuffer().toString();