JAVA 持续时间

Question

我有一个应用程序，我需要检查旅行的持续时间是否在 4 小时到 30 小时之间，我将其存储为字符串 "04:00" 和 "30:00 "，然后我尝试使用 LocalTime.parse() 对其进行解析，"04:00" 已成功解析，但 "30:00" 收到无效格式错误，从字符串中解析持续时间的最佳方法是什么？

Answer 1

首先，您以某种方式存储它是错误的。我建议以 Duration.parse 的方式存储它可以处理，标准 ISO 8601格式。

Examples:

    "PT20.345S" -- parses as "20.345 seconds"
    "PT15M"     -- parses as "15 minutes" (where a minute is 60 seconds)
    "PT10H"     -- parses as "10 hours" (where an hour is 3600 seconds)
    "P2D"       -- parses as "2 days" (where a day is 24 hours or 86400 seconds)
    "P2DT3H4M"  -- parses as "2 days, 3 hours and 4 minutes"
    "P-6H3M"    -- parses as "-6 hours and +3 minutes"
    "-P6H3M"    -- parses as "-6 hours and -3 minutes"
    "-P-6H+3M"  -- parses as "+6 hours and -3 minutes"

那么你可以这样做:

Duration dur30H = Duration.parse("PT30H"); // 30h
Duration dur4H = Duration.parse("PT4H"); // 4h
Duration travelTime = Duration.parse("P1D"); // 1D
boolean result = travelTime.compareTo(dur30H) <= 0 && travelTime.compareTo(dur4H) >= 0; // true