java - 如何一次打印所有输出而不是一次打印一个 - JAVA

Question

package validation;
import java.util.*;

public class Validation {
    public static void main(String[] args) {
        Scanner input = new Scanner(System.in);
        String regex = "^[a-zA-Z ]+$";
       String regex1 = "\\d[0-9]|[1-9]";
       String regex2 = "^[a-zA-Z0-9 ]+$";
        String Char;
         String num;
        String chars;
         System.out.println("WELCOME TO Mixed Martial Art's CLUB REGISTRATION");
        do{
            System.out.print("\nWhat Is Your Name:");
            Char = input.nextLine();

            if (Char.matches(regex))
                System.out.println("\nWelcome:"+" "+Char); 
            else if (Char.isEmpty())
                System.out.println("String field should not be Empty.");
            else if(!Char.matches(regex))
                System.out.println("Please Enter A Valid String!");
        } while(!Char.matches(regex));

        do {    
             System.out.print("\nHow Old Are you:");
             num = input.nextLine();
             if (num.isEmpty())
                 System.out.println("Number field should not be Empty.");       
             else if (!num.matches(regex1)){
                System.out.println("Please Enter A Valid Number!");
             } else{
                if(Integer.parseInt(num)<=18){
                   System.out.println("Sorry But You Are Underage.");                

                } else {
                    if (Integer.parseInt(num)<=39) {
                        System.out.println("You Are Qualified");
                    } else {
                        System.out.println("Opps! You Are OVER AGE!");
                    }
                }                     
            }
        }while(!num.matches(regex1));           
    }   
}

上面的代码按我的预期工作，但我需要更改有关最终打印输出的一些内容。我想要的是在输入所有详细信息后立即打印所有输出。

Answer 1

使用StringBuilder建立你的输出:

StringBuilder sb = new StringBuilder();
sb.append("Thank you for registering.\n");
sb.append("Please verify your data:\n");
//...

System.out.println(sb.toString());