java - Libgdx - 大约 2 人游戏。我希望每个玩家都可以用一根手指触摸自己的区域

Question

我正在创建 2 名玩家的游戏，每个玩家都有自己的区域。我希望每个玩家都可以用一根手指触摸自己的区域。所以首先我将“达阵”功能限制为“2 个指针”。

public boolean touchDown(int screenX, int screenY, int pointer, int button){
    if(pointer > 1){
        return false;
    }
    Gdx.app.log("", "pointer: "+pointer);

    return false;
}

但问题是，如果一名玩家用两根手指触摸自己的区域，另一名玩家将无法触摸自己的区域。我该如何解决这个问题？谢谢。

Answer 1

您不应该根据指针编号拒绝。

如果您想允许第一个指针在屏幕的每一侧向下，您可以执行以下操作(未经测试):

private int player1Pointer = -1, player2Pointer = -1;
private int player1X, player1Y, player2X, player2Y;

//...

public boolean touchDown(int screenX, int screenY, int pointer, int button){

    // Assuming top and bottom halves of screen:
    if (screenY > Gdx.graphics.getHeight() / 2){ // player 1 side
        if (player1Pointer >= 0) // player 1 already touching somewhere
            return false;
        player1Pointer = pointer;
        player1X = screenX;
        player1Y = screenY;
    } else { //player 2 side
        if (player2Pointer >= 0) // player 2 already touching somewhere
            return false;
        player2Pointer = pointer;
        player2X = screenX;
        player2Y = screenY;
    }
    return true;
}

public boolean touchDragged (int screenX, int screenY, int pointer) {
    if (pointer == player1Pointer){
        player1X = screenX;
        player1Y = screenY;
        return true;
    }
    if (pointer == player2Pointer){
        player2X = screenX;
        player2Y = screenY;
        return true;
    }
    return false;
}

public boolean touchUp (int screenX, int screenY, int pointer, int button) {
    if (pointer == player1Pointer){
        player1Pointer = -1;
        return true;
    }
    if (pointer == player2Pointer){
        player2Pointer = -1;
        return true;
    }
    return false;
}