java - OffsetDateTime toString() 返回不同格式的日期字符串

Question

我有这种格式的日期 yyyy-MM-dd'T'HH:mm:ss'Z'，但是当我使用 OffsetDateTime.parse(date) 解析它时; 它通过消除 seconds

返回字符串

逻辑:从日期中获取日期，如果是星期六或星期日，将日期更改为星期一并返回日期字符串

String date = "2018-12-30T06:00:00Z";

System.out.println(date);

try {
    OffsetDateTime dateTime = OffsetDateTime.parse(date);

    System.out.println(dateTime);           //2018-12-30T06:00Z

    DayOfWeek day = dateTime.getDayOfWeek();
    // check if price change  date is Sunday or Saturday and change it to Monday
    if (day.equals(DayOfWeek.SATURDAY) || day.equals(DayOfWeek.SUNDAY)) {

        String finalDateTime = dateTime.with(TemporalAdjusters.next(DayOfWeek.MONDAY)).toString();
         System.out.println(finalDateTime);      //2018-12-31T06:00Z
    }else {
        System.out.println(date);
    }
    }catch(Exception ex) {
        System.out.println(ex);
        System.out.println(date);
    }   

我需要返回与输入格式相同的字符串 yyyy-MM-dd'T'HH:mm:ss'Z'

Answer 1

根据 OffsetDateTime.toString()方法 javadoc 使用值的最短可能格式，而省略的部分隐含为零。 2018-12-30T06:00:00Z 的最短可能格式是 uuuu-MM-dd'T'HH:mmXXXXX 因此跳过秒和纳米:

The output will be one of the following ISO-8601 formats:

• uuuu-MM-dd'T'HH:mmXXXXX
• uuuu-MM-dd'T'HH:mm:ssXXXXX
• uuuu-MM-dd'T'HH:mm:ss.SSSXXXXX
• uuuu-MM-dd'T'HH:mm:ss.SSSSSSXXXXX
• uuuu-MM-dd'T'HH:mm:ss.SSSSSSSSSXXXXX

The format used will be the shortest that outputs the full value of the time where the omitted parts are implied to be zero.

如果您需要精确的格式，请使用具有特定模式的 DateTimeFormatter 实例来输出日期:

String date = "2018-12-30T06:00:00Z";
OffsetDateTime dt = OffsetDateTime.parse(date);
DateTimeFormatter fmt = DateTimeFormatter.ofPattern("yyyy-MM-dd'T'HH:mm:ss'Z'");
System.out.println(fmt.format(dt));