java - Cucumber 特征文件 - 解析为对象

Question

我想知道是否有人知道如何将 Cucumber 功能文件(无需执行或任何其他操作)解析为 Java 中的功能对象？

Answer 1

对于我正在从事的一个项目。我需要将功能文件解析为 Java 对象以供进一步处理和使用。我创建了一个映射器类(如上所述)并使用了以下代码:

import com.fasterxml.jackson.databind.ObjectMapper;
import com.fasterxml.jackson.dataformat.yaml.YAMLFactory;
import gherkin.formatter.JSONFormatter;
import gherkin.parser.Parser;
import gherkin.util.FixJava;
import java.io.File;
import java.io.FileInputStream;
import java.io.InputStreamReader;

public Feature[] getFeatures(String filepath) throws Exception {

        //Step One: Parse feature into JSON using Gherkin
        String featureText = FixJava.readReader(new InputStreamReader(new FileInputStream(filepath), "UTF-8"));
        StringBuilder json = new StringBuilder();
        JSONFormatter formatter = new JSONFormatter(json);
        Parser parser = new Parser(formatter);
        parser.parse(featureText, filepath, 0);
        formatter.done();
        formatter.close();

        //Step Two: Convert the Features to plain old java object, and return an array of features
        ObjectMapper mapper = new ObjectMapper();
        return mapper.readValue(json.toString(), Feature[].class);
}

这是要点 => https://gist.github.com/jatin-sethi/7c6f6a95a2e7dd0ea12fce105070aa40 .