java - org.hibernate.QueryException : could not resolve property: query of: abc. def.mypackage.orm.Employee

Question

当我尝试执行 insertEmployeeDetails 方法时，出现以下错误:

org.hibernate.QueryException:无法解析属性:查询:abc.def.mypackage.orm.Employee [INSERT INTO Employee(名称，定义，(从COMPANY_DATA中选择value_emp_id，其中testing_id = 1234 AND company_employee_id = 3345)) ]

查看有关 Stack Overflow 的类似在线其他帖子，例如以下内容:

org.hibernate.QueryException: could not resolve property:

“我们不引用数据库列名称，而是引用属性名称”。所以我明确提到了名称和definition，如下面的实体类Employee 中所定义。我尝试获取列 COLUMN_ID 值的子查询使用子查询，因此我不确定是否能够使用符合 HQL 规则的内容？我的意思是 应该从 COMPANY_DATA 表中提取 value_emp_id 的 SELECT 子查询是我提到过的 SQL 查询。那需要修改吗？这可能是此类错误的原因吗？请指教。

我的实体类Employee.java如下:

package abc.def.mypackage.orm

@Entity
@Table(name = "EMPLOYEE")
public class Employee {
 public int getEmployeeId() {
  return employeeId;
 }

 public void setEmployeeId(int employeeId) {
  this.employeeId = employeeId;
 }

 public String getName() {
  return name;
 }

 public void setName(String name) {
  this.name = name;
 }

 public int getIsCorrect() {
  return isCorrect;
 }

 public void setIsCorrect(int isCorrect) {
  this.isCorrect = isCorrect;
 }

 public int getIsWrong() {
  return isWrong;
 }

 public void setIsWrong(int isWrong) {
  this.isWrong = isWrong;
 }

 public int getCompanyId() {
  return companyId;
 }

 public void setCompanyId(int companyId) {
  this.companyId = companyId;
 }

 public Integer getTransactionId() {
  return transactionId;
 }

 public void setTransactionId(Integer transactionId) {
 this.transactionId = transactionId;
 }

 public String getDefinition() {
  return definition;
 }

 public void setDefinition(String definition) {
  this.definition = definition;
 }

 @Id
 @Column(name = "EMPLOYEE_ID")
 @GeneratedValue(strategy = GenerationType.AUTO, generator = "seqgen")
 @SequenceGenerator(name = "seqgen", sequenceName = "EMPLOYEE_AUTOINC_SEQ")
 private int employeeId;

 @Column(name = "NAME")
 private String name;

 @Column(name = "DEFINITION")
 private String definition;

 @Column(name = "IS_CORRECT")
 private int isCorrect;

 @Column(name = "IS_WRONG")
 private int isWrong;

 @Column(name = "COMPANY_ID")
 private int companyId;

 @Column(name = "TRANSACTION_ID", nullable = true)
 private Integer transactionId;


}

以下是我在方法中使用 HQL 的方式:

public boolean insertEmployeeDetails(Employee employee)
    {
        logger.debug("Starting EmployeeDaoImpl.insert()  .....");
        Session session = null;
        Transaction tx = null;
        boolean status = true;
        try {
            session = sessionFactory.openSession();
            tx = session.beginTransaction();
            String hqlInsert = "INSERT INTO Employee (name,definition,"
                    + "( SELECT value_emp_id FROM COMPANY_DATA WHERE testing_id = 1234 AND"
                    + " company_employee_id = 3345))";

            int createdEntities = session.createQuery( hqlInsert )
                    .executeUpdate();

            session.persist(employee);
            tx.commit();
            System.out.println("Checking for hqlInsert");
            System.out.println(hqlInsert);

            System.out.println("Checking for CreatedEntities");
            System.out.println(createdEntities);
        } catch(Exception ex) {
            tx.rollback();
            ex.printStackTrace();
            status = false;
        } finally {
            session.close();
        }
        logger.debug("Completed EmployeeDaoImpl.insert()  .....");
        return status;
    }

Answer 1

这里的问题是你混淆了 createQuery() 与 createSQLQuery() ，因为 createQuery() 执行 HQL 查询，而不是您在文档中看到的 SQL 查询:

createQuery

Create a new instance of Query for the given HQL query string.

事实上，您传递给 createQuery() 方法的 hqlInsert 查询 string 是一个 SQL 插入查询， createQuery() 不支持，您需要使用 createSQLQuery() 以便可以使用 Hibernate 执行它，并确保使用数据库列而不是实体属性，因为它是 SQL 查询。