javascript - 如何在上一个描述出错时跳到下一个描述()？ Jasmine 测试

Question

我使用这样的代码是为了在 it() 函数之一出现错误时停止整个 describe:

if(this.results_.failedCount > 0) {
        //next step will finish the test
   jasmine.Queue.prototype.next_ = function () {
   // to instead skip to the end
        this.onComplete();
   }
}

我从:How can I make jasmine.js stop after a test failure?

但是，如果文件中的描述 block 很少，并且第一个描述失败，我希望它继续下一个描述而不是终止整个测试。我该怎么做？

谢谢

Answer 1

亚设，我已经在 afterEach 中使用了您的解决方法中的代码，它似乎有效。谢谢 :)如果您希望其他规范失败(而不仅仅是跳过)在 if 中添加以下代码:

if (currentIt && (currentIt.results_.failedCount !== 0)) {

    var currentSuite = jasmine.getEnv().currentSpec.suite.id;
    var currentSpec = jasmine.getEnv().currentSpec.id;

    //get number of children (its)
    var numChildren = jasmine.getEnv().currentSpec.suite.children().length;

    //skip after last child
    jasmine.getEnv().currentRunner().suites()[currentSuite].queue.index = numChildren-1;
    //finish the current spec now (otherwise the spec will be reported after his siblings)
    jasmine.getEnv().currentSpec.finish();
    jasmine.getEnv().currentSpec.finishCallback = function(){};

    //report the other sibilings as failures
    for (var index = currentSpec+1; index < numChildren ; index++){
       var spec = jasmine.getEnv().currentSpec.suite.children()[index];
       jasmine.getEnv().currentSpec = spec;
       (new AddIndexPlugin()).doBefore();

       spec.results().failedCount = 1;
       spec.results().totalCount = 1;
       spec.results().skipped = true;
       spec.results().getItems().push(new jasmine.ExpectationResult({actual:'skipping test because previous test failed',passed:false , message:'skipping test because previous test failed',trace:'skipping test because previous test failed'}));

       spec.finish();
}

现在 Jasmine 确实是一个端到端的测试框架，而不仅仅是单元测试框架。