java - 如何将RestTemplate映射为多个响应内容？

Question

我必须使用带有 RestTemplate 的 REST API，但它不遵循良好的模式，例如使用 HTTP 状态代码。

我有以下两个回复内容。

成功响应:

{
    "435": {
        "Codigo": "435",
        "Tipo": "",
        "Corretor": "62",
        "Cliente": "48304",
        "DataHora": "2016-04-27 14:18:24",
        "DataHoraAtualizacao": "",
        "Assunto": "Visita - Imóvel 2",
        "Local": "",
        "Texto": "",
        "DataHoraInicio": "2016-04-28 12:00:00",
        "DataHoraFinal": "2016-04-28 12:20:00"
    },
    "687": {
        "Codigo": "687",
        "Tipo": "",
        "Corretor": "20",
        "Cliente": "33040",
        "DataHora": "2016-07-18 17:09:28",
        "DataHoraAtualizacao": "",
        "Assunto": "Visita - Imóvel 2",
        "Local": "",
        "Texto": "teste",
        "DataHoraInicio": "2016-07-28 08:00:00",
        "DataHoraFinal": "2016-07-28 09:00:00"
    }}

我们可以记下一个 map 结构，如下所示::

Map<String, MyObject> myObjects;

MyObject 类

public class MyObject {

    @JsonProperty("Codigo")
    private String codigo;

    @JsonProperty("Tipo")
    private String tipo;

    @JsonProperty("Corretor")
    private String corretor;

    @JsonProperty("Cliente")
    private String cliente;

    @JsonProperty("DataHora")
    private String dataHora;

    @JsonProperty("DataHoraAtualizacao")
    private String dataHoraAtualizacao;

    @JsonProperty("Assunto")
    private String assunto;

    @JsonProperty("Local")
    private String local;

    @JsonProperty("Texto")
    private String texto;

    @JsonProperty("DataHoraInicio")
    private String dataHoraInicio;

    @JsonProperty("DataHoraFinal")
    private String dataHoraFinal;

} 

错误响应(没有要返回的对象):

{
    "status": "200",
    "message": "A pesquisa não retornou resultados."
}

我应该如何映射 Java 类才能解决这两种情况？

Answer 1

嗯...那个 API 太糟糕了，你能要求他们改变它吗？至少要使用正确的 HTTP 代码？

如果没有，您可以先反序列化为 Map<String, JsonNode>然后取决于 status 的存在字段，反序列化为适当的类型:

String json = ...
Map<String, JsonNode> response = mapper.readValue(json, ...);

if (response.get("status") != null) {
    // its an error, deserialize into Error type
    Error error = mapper.readValue(json, Error.class);
else {
    // not an error, deserialize into MyObject
    MyObject obj = mapper.readValue(json, MyObject.class);
}