javascript - 在 rpivottable 中分组排序

Question

感谢 R 中的 rpivotTable 包，我已经使用这段代码生成了一个 rpivottable:

library("rpivotTable")
library("dplyr")
library("reshape2")

dane <- melt(HairEyeColor)

rpivotTable(dane,
            rows = c("Hair", "Eye"),
            cols = c("Sex"),
            vals = "value",
            aggregatorName = "Integer Sum",
            locale = "en",
            rendererName = "Table With Subtotal",
            subtotals = TRUE)

看起来像这样:

它是按字母顺序排列的。我想使用值的总和按降序对其进行排序。

我可以这样尝试:

library("rpivotTable")
library("dplyr")
library("reshape2")

dane <- melt(HairEyeColor)

sorter <- paste0("function(attr) {",
                 "var sortAs = $.pivotUtilities.sortAs;",
                 "if (attr == \"Eye\") { return sortAs([\"",
                 dane %>% group_by(Eye) %>% summarise(i = sum(value)) %>% arrange(-i) %>% .$Eye %>% paste(collapse = "\", \""),
                 "\"]); }",
                 "if (attr == \"Hair\") { return sortAs([\"",
                 dane %>% group_by(Hair) %>% summarise(i = sum(value)) %>% arrange(-i) %>% .$Hair %>% paste(collapse = "\", \""),
                 "\"]); }",
                 "}")

rpivotTable(dane,
            rows = c("Hair", "Eye"),
            cols = c("Sex"),
            vals = "value",
            aggregatorName = "Integer Sum",
            locale = "en",
            rendererName = "Table With Subtotal",
            subtotals = TRUE,
            sorters = sorter)

我明白了:

这是按“外部”组排序的。我想像这里一样按两个组对它进行排序:

在 rpivotTable 包中可以吗？

Answer 1

我从你的问题中学到的可能比你从我的回答中学到的更多，因为我喜欢你巧妙地混合 dplyr 和 JavaScript。为了重申您的问题，您在排序器函数中指定了一个眼睛排序列表，但您确实需要一个不同的眼睛排序列表，具体取决于头发分组。所以你的眼睛排序列表:

library("dplyr")
library("reshape2")

dane <- melt(HairEyeColor)
dane %>% group_by(Eye) %>% summarise(i = sum(value)) %>% 
   arrange(-i) %>% .$Eye %>% paste(collapse = "\", \"")

...有这样的输出:

"Brown\", \"Blue\", \"Hazel\", \"Green"

...这与每个 头发分组中使用的排序顺序相同。另见 this answer .

我不是数据透视表方面的专家，但为了做你想做的事，我认为排序函数必须处理两个属性，比如 [\"Hair\",\"Eye\"]，不止一个。我相信像这样的 dplyr 表达式会让你得到正确的二维列表:

dane %>% group_by(Hair, Eye) %>% 
  summarise(hairEyeSum = sum(value)) %>% 
  ungroup() %>% 
  arrange( desc(hairEyeSum)) %>% 
  group_by( Hair) %>% 
  mutate( hairSum = sum(hairEyeSum)) %>% 
  arrange( desc(hairSum), desc(hairEyeSum)) %>%
  ungroup() %>% 
  transmute( hairEyeList = paste0( "[\"", Hair, "\",\"", Eye, "\"]")) 

输出:

# A tibble: 16 x 1
   hairEyeList            
   <chr>                  
 1 "[\"Brown\",\"Brown\"]"
 2 "[\"Brown\",\"Blue\"]" 
 3 "[\"Brown\",\"Hazel\"]"
 4 "[\"Brown\",\"Green\"]"
 5 "[\"Blond\",\"Blue\"]" 
 6 "[\"Blond\",\"Green\"]"
 7 "[\"Blond\",\"Hazel\"]"
 8 "[\"Blond\",\"Brown\"]"
 9 "[\"Black\",\"Brown\"]"
10 "[\"Black\",\"Blue\"]" 
11 "[\"Black\",\"Hazel\"]"
12 "[\"Black\",\"Green\"]"
13 "[\"Red\",\"Brown\"]"  
14 "[\"Red\",\"Blue\"]"   
15 "[\"Red\",\"Hazel\"]"  
16 "[\"Red\",\"Green\"]" 

但我没有让排序器功能正常工作。