java - 即使返回后函数也会重复

Question

我正在与电脑玩家制作井字游戏。但是，每当我调用计算机的 makeMove 方法时，计算机都会继续播放，而用户无法执行任何操作。为了确保该函数停止，我让它在每次移动后返回，但它仍然可以在没有用户输入的情况下玩整个游戏。

以下是相关部分:

板类:

public String addToBoard(char c, int square) {
        if (!spaceFull(board, square)) {
            int[] coords = getRowAndColumn(square);
            //System.out.println("[" + coords[0] + "][" + coords[1] + "]");
            board[coords[0]][coords[1]] = c;
            return "VALID";
        } else {
            System.out.println("Space Is Occupied");
            return "OCCUPIED";
        }
    }
public boolean spaceFull(char[][] b, int square) {
        return (twoDimenToOneDimen(b).get(square - 1) == 'X' || twoDimenToOneDimen(b).get(square - 1) == 'O');
    }

计算机类

public void makeMove() {
        int square;
        //Checks For Any Winning Computer Moves
        System.out.println("Here");
        if ((square = nextMoveWinCheck(playerChar)) != 0) {
            board.addToBoard(playerChar, square);
            return;
            //Checks For Any Opponent Winning Moves
        } else if ((square = nextMoveWinCheck(opponentChar)) != 0) {
            board.addToBoard(playerChar, square);
            return;
        } else {
            //Checks If Computer Has First Move
            if (boardEmpty()) {
                board.addToBoard(playerChar, 9);
                return;
            } else {
                //Moves Into Opposite Corner if Bottom Corner is Occupied By Itself
                if (!board.spaceFull(board.board,1) && board.board[2][2] == playerChar) {
                    board.addToBoard(playerChar, 1);
                    return;
                    //Move Into Center If Second Move or Possible
                } else if (!board.spaceFull(board.board,5)) {
                    board.addToBoard(playerChar, 5);
                    return;
                } else if ((square = emptyCorner()) != 0) {
                    board.addToBoard(playerChar, square);
                    return;
                } else {
                    board.addToBoard(playerChar, randomEmptySpot());
                    return;
                }
            }
        }
    }

如果你想要完整的代码，它是:

• Computer
• Board
• Player
• Tic-Tac-Toe Main Class

Answer 1

您的问题出在您的计算机类Computer上。在第 57 行，您将 board.board 分配给 tempBoard。然而 tempBoard 仍然保留对对象 board.board 的引用，因此您所做的任何修改都会反射(reflect)在实际的板上。要解决此问题，请将板值复制到临时板: http://www.java2s.com/Code/Java/Collections-Data-Structure/clonetwodimensionalarray.htm