java - 使用 Java 的 XML Splitter - 索引设置距标签的偏移量，省略开始空格

Question

我的源 xml 文件如下所示

   <?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE DocName PUBLIC "-//msg//msg1 Project_Name 1.1//EN" "My_Project_Name_V1_1.dtd">
<My_Project_Name dtdVersion="V1_1" fileName="Guidance_Document_SQL" softwareName="prototype" softwareVersion="0.1" productionDate="2012-01-02">
    <ApplicantFileReference>ABCD#1234</ApplicantFileReference>
    <ApplicantName languageCode="EF">Michael Smith</ApplicantName>
    <ApplicantNameLatin>Michael Smith </ApplicantNameLatin>
    <ProductTitle languageCode="EF">Some Example </InventionTitle>
    <TotalQuantity>88</TotalQuantity>
    <Example_Data exampleIDNumber="1">
        <Exm_Seq>
            <Exm_Seq_length>7</Exm_Seq_length>
            <Exm_Seq_type>MM</Exm_Seq_type>
            <Exm_Seq_div>PAT</Exm_Seq_div>
        <Exm_Seq>
    </Example_Data>

我正在拆分此文件并创建 2 个文件。一种是.header 文件，另一种是.body 文件。正文文件将从“Example_Data”标签开始。现在的问题是，当创建 .body 文件时，内容是从文件的开头开始创建的，而不考虑空格。如下:

<Example_Data exampleIDNumber="1">
            <Exm_Seq>
                <Exm_Seq_length>7</Exm_Seq_length>
                <Exm_Seq_type>MM</Exm_Seq_type>
                <Exm_Seq_div>PAT</Exm_Seq_div>
            <Exm_Seq>
        </Example_Data>

但是我也想考虑空格，因此正文文件中的内容从原始文件中的位置开始(在 4 个空格之后或 Example_Data 标记之前的任意数量的空格之后)。我可以硬编码 4 个空格，但是这对我的事业没有帮助，因为还有其他文件在此标记之前可能有更多空格)。

这是我正在编写的用于拆分的代码:

public class Splitter {
    public static void main(String[] args) {
        String charset = "UTF-8";
        String original = args[0];
        String stem = original.substring(0, original.length() - 4);
        String headName = stem + ".head";
        String bodyName = stem + ".body";
        String bodyStart ="<Example_Data";
        try {
            //get rid of existing split files
            File existing = new File(headName);
            if(existing.exists()){
                existing.delete();
                System.out.println("Old header File has been deleted");
            }
            existing = new File(bodyName);
            if(existing.exists()){
                existing.delete();
                System.out.println("Old body file has been deleted");
            }
            //read in original file
            StringBuilder fileData = new StringBuilder(1000);
            FileInputStream fis = new FileInputStream(original);
            InputStreamReader fileReader = new InputStreamReader(fis,charset);
            BufferedReader reader = new BufferedReader(fileReader);  
            char[] buf = new char[10];
            System.out.println("Reading xml file");
            int numRead = 0;
            while ((numRead = reader.read(buf)) != -1) {
                String readData = String.valueOf(buf, 0, numRead);
                fileData.append(readData);
                buf = new char[1024];
            }
            reader.close();
            String content = fileData.toString();
            System.out.println("File reading completed");
            //split
            System.out.println("File Splitting process Started");
            int indx = content.indexOf(bodyStart);
            String head = content.substring(0, indx - 1);
            String body = content.substring(indx);
            //write to head file
            OutputStreamWriter headFile = new OutputStreamWriter(new FileOutputStream(headName), charset);
            headFile.write(head);
            System.out.println("New header file created");
            //headFile.flush();
            headFile.close();
            //write body to body file
            OutputStreamWriter bodyFile = new OutputStreamWriter(new FileOutputStream(bodyName), charset);
            bodyFile.write(body);
            System.out.println("New body file created");
            bodyFile.close();
        } catch (FileNotFoundException e1) {
            e1.printStackTrace();
        } catch (IOException e1) {
            e1.printStackTrace();
        } finally {
            ;
        }
    }
}

我不知道如何解决这个问题。任何建议将不胜感激。

Answer 1

您可能正在寻找一些逻辑检查

如果分割一半之前的字符不是标签的右括号(>)，则假设它是在换行符上创建的。
如果假定是换行符，则找到 head 中的最后一个换行符。
在换行符上分割主体。
如果它不匹配换行符标准，则根据找到的索引进行拆分，因为 xml 可能全部没有换行符。

在线查看:https://ideone.com/0degt4

完成的代码:

String content ="   <?xml version=\"1.0\" encoding=\"UTF-8\"?>\n"+
"<!DOCTYPE DocName PUBLIC \"-//msg//msg1 Project_Name 1.1//EN\" \"My_Project_Name_V1_1.dtd\">\n"+
"<My_Project_Name dtdVersion=\"V1_1\" fileName=\"Guidance_Document_SQL\" softwareName=\"prototype\" softwareVersion=\"0.1\" productionDate=\"2012-01-02\">\n"+
"    <ApplicantFileReference>ABCD#1234</ApplicantFileReference>\n"+
"    <ApplicantName languageCode=\"EF\">Michael Smith</ApplicantName>\n"+
"    <ApplicantNameLatin>Michael Smith </ApplicantNameLatin>\n"+
"    <ProductTitle languageCode=\"EF\">Some Example </InventionTitle>\n"+
"    <TotalQuantity>88</TotalQuantity>\n"+
"    <Example_Data exampleIDNumber=\"1\">\n"+
"        <Exm_Seq>\n"+
"            <Exm_Seq_length>7</Exm_Seq_length>\n"+
"            <Exm_Seq_type>MM</Exm_Seq_type>\n"+
"            <Exm_Seq_div>PAT</Exm_Seq_div>\n"+
"        <Exm_Seq>\n"+
"    </Example_Data>";

// Define newline character to look for. \r \r\n \n         
String newLine = "\n";

// Where the body starts        
String bodyStart ="<Example_Data";

// Base index defined by bodyStart
int indx = content.indexOf(bodyStart);

// Grab the head.
String head = content.substring(0, indx - 1);

// Find the last index of newline
int lastNewline = head.lastIndexOf(newLine);
String body;
// If we found a newline in head and the character before our match isn't a closing bracket, get content from newline
if(lastNewLine != -1 && content.charAt(indx - 1) != '>') {
    body = content.substring(lastNewline + 1);
}
// business as usual
else {
    body = content.substring(indx);
}

System.out.println(body);