java - 如何在 Java 中创建一个包含带引号的字符串的字符串？

Question

我想将带有选项的字符串放入 Weka。选项字符串内部是 weka 分词器字符串，分词器字符串内部是定界符选项字符串。我收到错误消息“没有为 -delimiters 选项指定值。”如何格式化字符串？

这是我的代码:

String[] options = weka.core.Utils.splitOptions("weka.filters.unsupervised.attribute.StringToWordVector "
            + "-R first-last -W 1000 -prune-rate -1.0 -N 0 -stemmer weka.core.stemmers.NullStemmer "
            + "-stopwords-handler weka.core.stopwords.Null -M 1 -tokenizer "
            + "\"weka.core.tokenizers.NGramTokenizer -max 5 -min 1 -delimiters \" \\r\\n\\t.,;:\\\'\\\"()?!\"");

StringToWordVector remove = new StringToWordVector();

This question没有解决我的问题。

Answer 1

您收到的错误消息说它在 -delimeters 选项后找不到任何值。这样做的原因是 Weka 检测到字符串在 -delimeter 查询参数后立即以双引号结尾。其根本原因是出现在 weka.core.tokenizers.NGramTokenizer 术语之前的流氓引号，该术语属于 -tokenizer查询参数:

String[] options = weka.core.Utils.splitOptions("weka.filters.unsupervised.attribute.StringToWordVector "
        + "-R first-last -W 1000 -prune-rate -1.0 -N 0 -stemmer weka.core.stemmers.NullStemmer "
        + "-stopwords-handler weka.core.stopwords.Null -M 1 -tokenizer "
        + "\"weka.core.tokenizers.NGramTokenizer -max 5 -min 1 -delimiters \" \\r\\n\\t.,;:\\\'\\\"()?!\"");
           ^ rogue quotation mark.  Bad.

将字符串更改为以下内容应该没问题:

String[] options =
    weka.core.Utils.splitOptions(
        "weka.filters.unsupervised.attribute.StringToWordVector "
      + "-R first-last -W 1000 -prune-rate -1.0 -N 0 "
      + "-stemmer weka.core.stemmers.NullStemmer "
      + "-stopwords-handler weka.core.stopwords.Null -M 1 "
      + "-tokenizer weka.core.tokenizers.NGramTokenizer -max 5 -min 1 "
      + "-delimiters \" \\r\\n\\t.,;:\\\'\\\"()?!\"");