java - 如何从给定字符串获取描述中的预期输出

Question

[评分]:Bot-16 从 [Actor - Kill] 处获得 2.0 赏金 [受害者:Actor200_(Actor_Local_Minion_200)] [@152133]

如何格式化上述字符串以便获得以下输出:

玩家 ID = Bot-16

积分 = 2.0

Action = [ Actor -杀死]

受害者 = Actor200_(Actor_Local_Minion_200)

时间戳 = 152133

还有一些行没有受害者标签，如下面的字符串

[评分]:2 Dev 158744780 从 [Actor - Kill] [Ace] [@519382] 获得 20.0 赏金

输出应该是

玩家 ID = 2 Dev 158744780

积分 = 20.0

Action = Actor-Kill

受害者=艾斯

时间戳 = 519382

Answer 1

您可以使用正则表达式来处理这个问题。

查看您的输入字符串，我想出了这个正则表达式:

\[Scoring\]: (.*) got ([^\s]*) bounty from \[([^\]]*)\] \[(?:Victim: )?([^\]]*)\] \[@([^\]]*)\]

此处演示:https://regex101.com/r/e3zuKw/2

这是 Java 中的演示程序及其输出。我认为这将是您的解决方案。

输出:

**First Input**
Player-ID = Bot-16
Points = 2.0
Action = Actor - Kill
Victim = Actor200_(Actor_Local_Minion_200)
Timestamp = 152133

**Second Input**
Player-ID = 2 Dev 158744780
Points = 20.0
Action = Actor - Kill
Victim = Ace
Timestamp = 519382

代码:

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class Demo {
    public static void main(String[] args) {
        System.out.println("**First Input**");
        printInfo("[Scoring]: Bot-16 got 2.0 bounty from [Actor - Kill] [Victim: Actor200_(Actor_Local_Minion_200)] [@152133]");

        System.out.println("\n**Second Input**");
        printInfo("[Scoring]: 2 Dev 158744780 got 20.0 bounty from [Actor - Kill] [Ace] [@519382]");
    }

    public static void printInfo(String line) {
        String pattern = "\\[Scoring\\]: (.*) got ([^\\s]*) bounty from \\[([^\\]]*)\\] \\[(?:Victim: )?([^\\]]*)\\] \\[@([^\\]]*)\\]";

        Pattern r = Pattern.compile(pattern);
        Matcher m = r.matcher(line);

        if (m.find()) {
            System.out.println("Player-ID = " + m.group(1));
            System.out.println("Points = " + m.group(2));
            System.out.println("Action = " + m.group(3));
            System.out.println("Victim = " + m.group(4));
            System.out.println("Timestamp = " + m.group(5));
        }
    }
}