java - 使用java中的startsWith方法删除LinkedList元素

Question

我正在尝试删除以 r 和 g 开头的列表元素

一个条件工作正常，可以删除从 r 开始的元素，但下一个条件在 if 循环中不起作用，帮助我解决我犯错误的地方。谢谢..!!

我的代码是

import java.util.Arrays;
import java.util.LinkedList;

public class EasyRemovingList {
    void removeList(){
    String[] inpArray={"red","green","blue","ivory"};
    LinkedList<String> upList = new LinkedList<String>(Arrays.asList(inpArray));
    System.out.println("Actual "+upList+" "+upList.size());
    //System.out.println(upList.get(3));
    for(int i = 0;i<upList.size();i++){
        //System.out.println(upList.get(i));    
    if(upList.get(i).startsWith("r")||upList.get(i).startsWith("g")){
        upList.remove(i);
        System.out.println("Updated "+upList);
    }
    }
    //System.out.println(upList);
    }
    public static void main(String[] args) {
        // TODO Auto-generated method stub
        EasyRemovingList er = new EasyRemovingList();
        er.removeList();

    }

}

输出为

Actual [red, green, blue, ivory] 4
Updated [green, blue, ivory]

预期输出为

Actual [red, green, blue, ivory] 4
Updated [blue, ivory]

Answer 1

尝试使用removeIf()。

upList.removeIf(element -> {return element.starts("r") || element.startsWith("g");});

MVCE

import java.util.Arrays;
import java.util.LinkedList;

/**
 *
 * @author Sedrick
 */
public class JavaApplication4 {

    /**
     * @param args the command line arguments
     */
    public static void main(String[] args) {
        String[] inpArray={"red","green","blue","ivory"};
        LinkedList<String> upList = new LinkedList(Arrays.asList(inpArray));
        System.out.println("Actual "+upList+" "+upList.size());

        upList.removeIf(element -> {
            return element.startsWith("r") || element.startsWith("g"); //To change body of generated lambdas, choose Tools | Templates.
        });

        System.out.println("Actual "+upList+" "+upList.size());

    }

}

Results

run:
Actual [red, green, blue, ivory] 4
Actual [blue, ivory] 2
BUILD SUCCESSFUL (total time: 0 seconds)