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java - 如果我在并行流中使用 lambda 会发生死锁,但如果我改用匿名类则不会发生死锁?

转载 作者:行者123 更新时间:2023-11-30 06:02:46 25 4
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以下代码导致死锁(在我的电脑上):

public class Test {
static {
final int SUM = IntStream.range(0, 100)
.parallel()
.reduce((n, m) -> n + m)
.getAsInt();
}

public static void main(String[] args) {
System.out.println("Finished");
}
}

但是如果我用匿名类替换 reduce lambda 参数,它不会导致死锁:

public class Test {
static {
final int SUM = IntStream.range(0, 100)
.parallel()
.reduce(new IntBinaryOperator() {
@Override
public int applyAsInt(int n, int m) {
return n + m;
}
})
.getAsInt();
}

public static void main(String[] args) {
System.out.println("Finished");
}
}

你能解释一下这种情况吗?

附言

我找到了那个代码(和以前的有点不同):

public class Test {
static {
final int SUM = IntStream.range(0, 100)
.parallel()
.reduce(new IntBinaryOperator() {
@Override
public int applyAsInt(int n, int m) {
return sum(n, m);
}
})
.getAsInt();
}

private static int sum(int n, int m) {
return n + m;
}

public static void main(String[] args) {
System.out.println("Finished");
}
}

工作不稳定。在大多数情况下,它会挂起,但有时会成功完成:

enter image description here

我真的无法理解为什么这种行为不稳定。实际上我重新测试了第一个代码片段并且行为相同。所以最新的代码等于第一个。

为了了解使用了哪些线程,我在“日志记录”之后添加了:

public class Test {
static {
final int SUM = IntStream.range(0, 100)
.parallel()
.reduce((n, m) -> {
System.out.println(Thread.currentThread().getName());
return (n + m);
})
.getAsInt();
}

public static void main(String[] args) {
System.out.println("Finished");
}
}

如果应用程序成功完成,我会看到以下日志:

main
main
main
main
ForkJoinPool.commonPool-worker-1
ForkJoinPool.commonPool-worker-1
ForkJoinPool.commonPool-worker-1
ForkJoinPool.commonPool-worker-1
ForkJoinPool.commonPool-worker-1
ForkJoinPool.commonPool-worker-1
ForkJoinPool.commonPool-worker-1
ForkJoinPool.commonPool-worker-1
ForkJoinPool.commonPool-worker-1
ForkJoinPool.commonPool-worker-1
ForkJoinPool.commonPool-worker-1
ForkJoinPool.commonPool-worker-1
ForkJoinPool.commonPool-worker-1
ForkJoinPool.commonPool-worker-1
ForkJoinPool.commonPool-worker-1
ForkJoinPool.commonPool-worker-1
ForkJoinPool.commonPool-worker-1
ForkJoinPool.commonPool-worker-1
ForkJoinPool.commonPool-worker-1
ForkJoinPool.commonPool-worker-1
ForkJoinPool.commonPool-worker-1
ForkJoinPool.commonPool-worker-1
ForkJoinPool.commonPool-worker-1
ForkJoinPool.commonPool-worker-1
main
ForkJoinPool.commonPool-worker-1
ForkJoinPool.commonPool-worker-1
ForkJoinPool.commonPool-worker-1
ForkJoinPool.commonPool-worker-1
ForkJoinPool.commonPool-worker-1
ForkJoinPool.commonPool-worker-1
ForkJoinPool.commonPool-worker-1
ForkJoinPool.commonPool-worker-1
ForkJoinPool.commonPool-worker-1
ForkJoinPool.commonPool-worker-1
ForkJoinPool.commonPool-worker-1
ForkJoinPool.commonPool-worker-1
main
main
main
main
main
main
main
main
main
main
main
main
main
main
main
main
main
ForkJoinPool.commonPool-worker-1
ForkJoinPool.commonPool-worker-1
ForkJoinPool.commonPool-worker-1
ForkJoinPool.commonPool-worker-1
ForkJoinPool.commonPool-worker-1
main
main
main
main
main
main
main
main
main
main
main
main
main
main
main
main
main
main
main
main
main
main
main
main
main
main
main
ForkJoinPool.commonPool-worker-1
ForkJoinPool.commonPool-worker-1
ForkJoinPool.commonPool-worker-1
ForkJoinPool.commonPool-worker-1
ForkJoinPool.commonPool-worker-1
ForkJoinPool.commonPool-worker-1
ForkJoinPool.commonPool-worker-1
ForkJoinPool.commonPool-worker-1
ForkJoinPool.commonPool-worker-1
Finished

附言2

我不明白 reduce 是足够复杂的操作。我找到了一个更简单的例子来说明这个问题:

public class Test {
static {
System.out.println("static initializer: " + Thread.currentThread().getName());

final long SUM = IntStream.range(0, 2)
.parallel()
.mapToObj(i -> {
System.out.println("map: " + Thread.currentThread().getName() + " " + i);
return i;
})
.count();
}

public static void main(String[] args) {
System.out.println("Finished");
}
}

对于快乐案例(罕见案例)我看到以下输出:

static initializer: main
map: main 1
map: main 0
Finished

扩展流范围的满意案例示例:

static initializer: main
map: main 2
map: main 3
map: ForkJoinPool.commonPool-worker-2 4
map: ForkJoinPool.commonPool-worker-1 1
map: ForkJoinPool.commonPool-worker-3 0
Finished

导致死锁的例子:

static initializer: main
map: main 1

它也会导致死锁,但不是每次启动都会导致死锁。

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