java - 如何在抛出异常后循环程序

Question

我有以下可能会抛出异常的代码:

import java.util.*;
import java.io.*;

class Test {
    public static void main (String [] args) {
        try {
            Scanner keyboard = new Scanner (System.in);
            int n1, n2;
            System.out.print("Type an int: ");
            n1 = keyboard.nextInt();
            System.out.print("Type another int: ");
            n2 = keyboard.nextInt();
            int r = n1/n2;
        }
        catch (ArithmeticException e) {
            System.out.println("Divide by 0");


        }
        catch (InputMismatchException e) {
            System.out.println("Wrong entry");
        }
    }
}

抛出异常后。我希望程序返回到要求用户再次输入一个新的整数而不是退出。

Answer 1

用 while (true) 包装你的代码，并在 try block 的末尾添加一个 break，这样它就会只有在没有抛出异常时才达到。

例如

while (true) {

    try {

        // your code goes here ....

        break;    // this will only be reached if no exceptions thrown
    }
    catch (...) { 

    }
};  // close the while loop

// this will be reached after the break only, i.e. no exceptions