java - 在 Java 8 中是否有更好的方法来检查这种情况？

Question

我需要简化以下java代码。有什么方法可以使用 set 并执行此操作吗？

      if (!(((AdministrativeState.PLANNED == dispensingOccasionModel.getOccasionDTO().getAdminState()) ||
             (AdministrativeState.MISSED == dispensingOccasionModel.getOccasionDTO().getAdminState()) ||
             (AdministrativeState.SKIPPED == dispensingOccasionModel.getOccasionDTO().getAdminState()) ||
             (AdministrativeState.SELF_ADMINISTERED == dispensingOccasionModel.getOccasionDTO().getAdminState()) ||
(AdministrativeState.SELF_ADMINISTERED_BY_RANGE == dispensingOccasionModel.getOccasionDTO().getAdminState())) &&
        isSpecialDoseType(doseDetail))

Answer 1

使用Set，您可以初始化有效的枚举类型并执行包含，正如@shmosel也在评论中指出的那样:

Set<AdministrativeState> administrativeStates = Set.of(PLANNED, MISSED, SKIPPED, SELF_ADMINISTERED, SELF_ADMINISTERED_BY_RANGE)
if (!administrativeStates.contains(dispensingOccasionModel.getOccasionDTO().getAdminState())
        || !isSpecialDoseType(doseDetail))