java - 如何使用变量和异常格式化错误日志

Question

import org.slf4j.Logger;
import org.slf4j.LoggerFactory;

    private static final Logger log = LoggerFactory.getLogger(Twitter.class);

        } catch (TwitterException e) {
            // It prints the message as well as the exception
            // log.error("Unable to show status", e);

            // I would like to pass a status as well as an exception
            // Is this an appropriate log statement
            String status = "failed";
            log.error("Unable to show status {}", status, e);
        }

上面的 log.error 语句是 log.error 的变体，上面的语句能正常工作吗？我不确定，因为我也通过了“状态”。请澄清

Answer 1

如果不确定，只需使用 String#format 创建日志消息:

log.error(String.format("Unable to show status %s", status), e);