java - 将 UUID 转换为十六进制字符串，反之亦然

Question

A UUID in the form of "b2f0da40ec2c11e00000242d50cf1fbf"has been transformed (see the following code segment) into a hex string as 6232663064613430656332633131653030303030323432643530636631666266. I want to code a reverse routine and get it back to the original format as in "b2f0.. ”，但很难做到，有什么帮助吗？

    byte[] bytes = uuid.getBytes("UTF-8");

    StringBuilder hex = new StringBuilder(bytes.length* 2);
    Formatter fmt = new Formatter(hex);

    for (byte b : bytes)
        fmt.format("%x", b);

Answer 1

final String input = "6232663064613430656332633131653030303030323432643530636631666266";
System.out.println("input: " + input);
final StringBuilder result = new StringBuilder();
for (int i = 0; i < input.length(); i += 2) {
    final String code = input.substring(i, i + 2);
    final int code2 = Integer.parseInt(code, 16);
    result.append((char)code2);

}
System.out.println("result: " + result);

它打印:

input: 6232663064613430656332633131653030303030323432643530636631666266
result: b2f0da40ec2c11e00000242d50cf1fbf