java - Hibernate完整性约束冲突: NOT NULL check constraint: For onetoOne Mapping using spring boot crud

Question

我正在尝试在两个表之间创建onetoone映射，其中父键主键也充当子表的主键。在尝试保存父级时，我收到以下错误。

请找到下面的控制台日志、模型类和服务类。有人可以帮助解决该错误吗？

主要是想使用 crud 存储库将订单 id 从订单类转移到补偿下的订单 id。

父类:

    package com.newModel;
import java.io.Serializable;

import javax.persistence.CascadeType;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.FetchType;
import javax.persistence.Id;
import javax.persistence.OneToOne;
import javax.persistence.Table;

@Entity
@Table(name="ORDERS")
public class Order implements Serializable {
    private static final long serialVersionUID = 1L;

    @Id
    @Column(name="ORDER_ID")
    private String orderId;

    @Column(name="ACCESS_ID")
    private String accessId;

    @OneToOne(cascade=CascadeType.ALL,mappedBy="order",fetch=FetchType.EAGER)
    private Compensation compensation;

//getters & setters 
    }

子类:

package com.newModel;

import java.io.Serializable;

import javax.persistence.CascadeType;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.Id;
import javax.persistence.JoinColumn;
import javax.persistence.MapsId;
import javax.persistence.NamedQuery;
import javax.persistence.OneToOne;
import javax.persistence.Table;



@Entity
@Table(name="COMPENSATION")
@NamedQuery(name="Compensation.findAll", query="SELECT o FROM Compensation o")
public class Compensation implements Serializable {
    private static final long serialVersionUID = 1L;

    /*@Id
    @Column(name="ORDER_ID")
    private String orderId;*/

    @Column(name="CHANNEL_DEALER_CODE")
    private String channelDealerCode;

    //bi-directional one-to-one association to Order

    @Id
    @OneToOne(cascade=CascadeType.ALL)
    @JoinColumn(name="ORDER_ID")
    private Order order;


}

服务等级:

package com.sample.service;

import javax.ws.rs.core.Response;

import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.stereotype.Component;

import com.newModel.Order;


@Component
public class MobilityServiceImpl implements MobilityService {


    @Autowired
    private MobilityRepository mobilityRepo;

    @Override
    public Response getOrderDetails(String orderId) {

        Order orderDetails=mobilityRepo.findByOrderId(orderId);

        return Response.ok(orderDetails).build();
    }

    @Override
    public Response saveOrderDetails(Order orderDetails) {

        orderDetails.getCompensation().setOrder(orderDetails);

        Order orderResponse =mobilityRepo.save(orderDetails);
        String resp=orderResponse.getOrderId()+" is Success";
        return Response.ok(resp).build();
    }

    }

控制台日志:

 Hibernate: select order0_.order_id as order_id1_1_1_, order0_.access_id as access_i2_1_1_, compensati1_.order_id as order_id2_0_0_, compensati1_.channel_dealer_code as channel_1_0_0_ from orders order0_ left outer join compensation compensati1_ on order0_.order_id=compensati1_.order_id where order0_.order_id=?
Hibernate: select compensati0_.order_id as order_id2_0_0_, compensati0_.channel_dealer_code as channel_1_0_0_ from compensation compensati0_ where compensati0_.order_id=?
Hibernate: insert into orders (access_id, order_id) values (?, ?)
Hibernate: insert into compensation (channel_dealer_code, order_id) values (?, ?)
2018-11-23 16:13:53.210  WARN 17532 --- [nio-8080-exec-1] o.h.engine.jdbc.spi.SqlExceptionHelper   : SQL Error: -10, SQLState: 23502
2018-11-23 16:13:53.211 ERROR 17532 --- [nio-8080-exec-1] o.h.engine.jdbc.spi.SqlExceptionHelper   : integrity constraint violation: NOT NULL check constraint; SYS_CT_10118 table: COMPENSATION column: ORDER_ID
2018-11-23 16:13:53.214 ERROR 17532 --- [nio-8080-exec-1] o.h.i.ExceptionMapperStandardImpl        : HHH000346: Error during managed flush [org.hibernate.exception.ConstraintViolationException: could not execute statement]
2018-11-23 16:13:53.244 ERROR 17532 --- [nio-8080-exec-1] o.a.c.c.C.[.[.[/].[dispatcherServlet]    : Servlet.service() for servlet [dispatcherServlet] in context with path [] threw exception [Request processing failed; nested exception is org.springframework.dao.DataIntegrityViolationException: could not execute statement; SQL [n/a]; constraint [null]; nested exception is org.hibernate.exception.ConstraintViolationException: could not execute statement] with root cause

org.hsqldb.HsqlException: integrity constraint violation: NOT NULL check constraint; SYS_CT_10118 table: COMPENSATION column: ORDER_ID

JSON 请求:

{
  "orderId": "1006730",
  "accessId": "1810_CRU",
  "compensation": {

                "channelDealerCode": "ABCD"
                }
}

Answer 1

在 Compensation 实体中，您仍然需要在单独的属性中拥有 id 和 Order 并使用 MapsId 来拥有相同的 id

@Entity
@Table(name="COMPENSATION")
@NamedQuery(name="Compensation.findAll", query="SELECT o FROM Compensation o")
public class Compensation implements Serializable {
    private static final long serialVersionUID = 1L;

    @Id
    private String id;

    @Column(name="CHANNEL_DEALER_CODE")
    private String channelDealerCode;

    @OneToOne(fetch = FetchType.LAZY)
    @MapsId
    private Order order;
}