java - 在 JTable 中鼠标悬停时创建信息面板？工具提示可能不够

Question

我想使用 Java Swing 在 JTable 单元格上显示一个信息框，所以有多个部分

1. 如何捕捉表格单元格中的鼠标悬停事件？我必须能够设置单元格内容，然后获取数据。
2. 如何在将鼠标悬停在该单元格上时显示带有动态服务器数据的面板/框？
3. 如何缓存信息面板/框，这样我就不必在每次鼠标悬停时都查询服务器？

例子:

在表格单元格中，我输入:94903。按 Tab 键或输入后，单元格设置为数字。鼠标悬停时，它会显示一个包含姓名、地址、电话号码、电子邮件等的框。

谢谢!

Answer 1

您可以使用 HTML 格式化工具提示文本，这将允许您向工具提示提供复杂的信息结构，而无需编写您自己的解决方案，也无需为此付出代价。唯一的问题是工具提示将被自动丢弃。

如果还是不行，你可以试试:

import java.awt.Point;
import java.awt.Rectangle;
import java.awt.event.*;
import javax.swing.JPopupMenu;
import javax.swing.JTable;
import javax.swing.Timer;

public class TestTable {

    private Timer showTimer;
    private Timer disposeTimer;
    private JTable table;
    private Point hintCell;
    private MyPopup popup; // Inherites from JPopupMenu

    public TestTable() {

        showTimer = new Timer(1500, new ShowPopupActionHandler());
        showTimer.setRepeats(false);
        showTimer.setCoalesce(true);

        disposeTimer = new Timer(5000, new DisposePopupActionHandler());
        disposeTimer.setRepeats(false);
        disposeTimer.setCoalesce(true);

        table.addMouseMotionListener(new MouseMotionAdapter() {

            @Override
            public void mouseMoved(MouseEvent e) {

                Point p = e.getPoint();
                int row = table.rowAtPoint(p);
                int col = table.columnAtPoint(p);

                if ((row > -1 && row < table.getRowCount()) && (col > -1 && col < table.getColumnCount())) {

                    if (hintCell == null || (hintCell.x != col || hintCell.y != row)) {

                        hintCell = new Point(col, row);
                        Object value = table.getValueAt(row, col);
                        // Depending on how the data is stored, you may need to load more data
                        // here...
                        // You will probably want to maintain a reference to the object hint data

                        showTimer.restart();

                    }

                }

            }
        });

    }

    protected MyPopup getHintPopup() {

        if (popup == null) {

            // Construct the popup...

        }

        return popup;

    }

    public class ShowPopupActionHandler implements ActionListener {

        @Override
        public void actionPerformed(ActionEvent e) {

            if (hintCell != null) {

                disposeTimer.stop(); // don't want it going off while we're setting up

                MyPopup popup = getHintPopup();
                popup.setVisible(false);

                // You might want to check that the object hint data is update and valid...
                Rectangle bounds = table.getCellRect(hintCell.y, hintCell.x, true);
                int x = bounds.x;
                int y = bounds.y + bounds.height;

                popup.show(table, x, y);

                disposeTimer.start();

            }

        }
    }

    public class DisposePopupActionHandler implements ActionListener {

        @Override
        public void actionPerformed(ActionEvent e) {

            MyPopup popup = getHintPopup();
            popup.setVisible(false);

        }
    }
}

现在，我还没有构建弹出窗口，我也会使用 Bob Sinclar 的回答中的弹出菜单