javascript - 如何在原型(prototype)中读取 json 对象

Question

我无法获取返回数据的属性。我对原型(prototype)很陌生。我的错误在哪里？

这是我的代码:

 <script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/prototype/1.7.1.0/prototype.js"></script>
<script>
    var xRequest = new Ajax.Request('PrototypeTest.aspx/Test', {
        method: 'post',
        contentType: 'application/json; charset=utf-8',
        onSuccess: function (val) {
            var brands= val.responseText.evalJSON();
            alert(brands);
        },
        onerror: function (val) {
            alert('hata');

        }
    });
</script>

   [WebMethod]
    public static string Test()
    {
        List<brand> brands = new List<brand>();
        brands.Add(new brand()
            {
                Name = "BMW",
                IsActive = true
            });

        var json = new JavaScriptSerializer();
        return json.Serialize(brands);
    }

Answer 1

你应该改变这一行

`var brands= val.responseText.evalJSON();` 

到

`var brands= JSON.parse((JSON.parse(val.responseText));` 

或

`var brands= val.responseText.evalJSON().d.evalJSON();`