个人中心
gpt4 book ai didi

C++ 如何在客户端中将 ledstatus 显示为打开或关闭？

转载 作者：行者123 更新时间：2023-11-30 05:42:12 25 4
gpt4 key购买 nike

代码是 Arduino C++ 如何在 HTTP 客户端中将 ledstatus 显示为“开”或“关”？if语句中的Led/status不像Ledstatus = off；或 Ledstatus = on；为什么？但如果我用数字代替，我做错了什么？

请帮忙？

/*
  Web Server

 A simple web server that shows the value of the analog input pins.
 using an Arduino Wiznet Ethernet shield.

 Circuit:
 * Ethernet shield attached to pins 10, 11, 12, 13
 * Analog inputs attached to pins A0 through A5 (optional)

 created 18 Dec 2009
 by David A. Mellis
 modified 9 Apr 2012
 by Tom Igoe

 */

#include <SPI.h>
#include <Ethernet.h>
#include <Wire.h>

// Enter a MAC address and IP address for your controller below.
// The IP address will be dependent on your local network:
byte mac[] = {
  0xDE, 0xAD, 0xBE, 0xEF, 0xFE, 0xED
};
IPAddress ip(10,0, 0, 210);
char linebuffer[20];
int linenumber = 0;

boolean IsLed = false;

// (Spa Variables):
int LedOn;
int Ledstatus;






// Initialize the Ethernet server library
// with the IP address and port you want to use
// (port 80 is default for HTTP):
EthernetServer server(80);


void setup() {
  // Open serial communications and wait for port to open:
  Serial.begin(9600);
  while (!Serial) {
    ; // wait for serial port to connect. Needed for Leonardo only
  }

  // Set Digital Pin 12 to output:
  pinMode(12,OUTPUT);

  // start the Ethernet connection and the server:
  Ethernet.begin(mac, ip);
  server.begin();
  Serial.print("server is at ");
  Serial.println(Ethernet.localIP());
  digitalWrite (12,LOW);
}


void loop() {
  // listen for incoming clients
  EthernetClient client = server.available();
  if (client) {
    Serial.println("new client");

    // an http request ends with a blank line
    boolean currentLineIsBlank = true;

    while (client.connected()) {
      if (client.available()) {
        char c = client.read();

        Serial.write(c);
        // if you've gotten to the end of the line (received a newline
        // character) and the line is blank, the http request has ended,
        // so you can send a reply
        if (c == '\n' && currentLineIsBlank){
          // send a standard http response header
          parseRequest();
          //sendHTTPResponse(client);
          client.println("HTTP/1.1 200 OK");
          client.println("Content-Type: text/html");
          client.println("Connection: close");  // the connection will be closed after completion of the response
          client.println("Refresh: 5");  // refresh the page automatically every 5 sec
          client.println();
          client.println("<!DOCTYPE HTML>");
          client.println("<html>");
          client.println("OK ");
          client.print(IsLed);
          client.print(Ledstatus);



          char linebuffer[20]; //Clear the line buffer
          linenumber = 0;

          break;

        }
        if (c == '\n'){
          // you're starting a new line
          currentLineIsBlank = true;
        }else if (c != '\r') {
          if(linenumber <20){ //If there is room in the buffer
            linebuffer[linenumber] = c; //Add char to the buffer
            linenumber++; //Increment the counter
         }
        // you've gotten a character on the current line
          currentLineIsBlank = false;
        }
      }
    }
    // give the web browser time to receive the data
    delay(10);
    // close the connection:
    client.stop();
    Serial.println("client disconnected");
  }
}

void parseRequest(){
  if(linebuffer[5] == 'O' && linebuffer[6] == 'N'){ //if the request was for ON 
  //Turn on the LED
  IsLed = true;
  digitalWrite (12,LOW);
  Serial.println("isLed ON");
  Ledstatus= on;

  }else{(linebuffer[5] == 'O' && linebuffer [6] == 'F' && linebuffer [7] == 'F'); //if the request was for OFF
  //Turn OFF the LED
  IsLed = false;
  digitalWrite(12,HIGH);
  Serial.println("isLed OFF");
  Serial.println();
  Ledstatus = off;
  }
} 

​

最佳答案

我想我终于找到你了，因为你的代码有些困惑!正如您在评论中所写，您会得到一个 OK10 或 OKOO 因为您正在代码中打印它:

...
client.println("HTTP/1.1 200 OK");
client.println("Content-Type: text/html");
client.println("Connection: close");  // the connection will be closed after completion of the response
client.println("Refresh: 5");  // refresh the page automatically every 5 sec
client.println();
client.println("<!DOCTYPE HTML>");
client.println("<html>");
client.println("OK ");   //Prints OK of course
client.print(IsLed);     //Prints an int!!
client.print(Ledstatus); //Also prints an int!!
...

你需要把它改成这样:

...
client.println("HTTP/1.1 200 OK");
client.println("Content-Type: text/html");
client.println("Connection: close");  // the connection will be closed after completion of the response
client.println("Refresh: 5");  // refresh the page automatically every 5 sec
client.println();
client.println("<!DOCTYPE HTML>");
client.println("<html>");
client.print("OK ");   //Prints OK of course
if(Ledstatus == on)
    client.println("ON");
else
    client.println("OFF");
...

还有我在评论中提到的，您没有从客户端读取行缓冲区，但您正在解析它。它将是空的!我不知道API，但必须有类似于

的功能 
client.read(linubuffer, 20);

关于C++ 如何在客户端中将 ledstatus 显示为打开或关闭？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/30755994/

25 4 0
文章推荐： c++ - 如何实现模板内部类函数(C++)
文章推荐： javascript - 在模式框中打开页面
文章推荐： c++ - 始终分配 vs 检查相等性并分配
文章推荐： javascript - 谷歌地图 V3，strokeWeight Polyline 可缩放
行者123
个人简介

我是一名优秀的程序员,十分优秀！

滴滴打车优惠券免费领取
滴滴打车优惠券
全站热门文章
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com