java - 如何在 Spring Security 中使用电子邮件作为用户名？

Question

我必须从我的 User 类中删除登录字段，并使用 email 作为 SecurityUtils 中的用户名

我已经更改了前端中的 j_username 参数，但现在问题仍然存在于后端

public static String getCurrentUserLogin() {
        SecurityContext securityContext = SecurityContextHolder.getContext();
        Authentication authentication = securityContext.getAuthentication();
        String userName = null;
        if (authentication != null) {
            if (authentication.getPrincipal() instanceof UserDetails) {
                UserDetails springSecurityUser = (UserDetails) authentication.getPrincipal();
                userName = springSecurityUser.getUsername();
            } else if (authentication.getPrincipal() instanceof String) {
                userName = (String) authentication.getPrincipal();
            }
        }
        return userName;
    }

结果userName为空，因为UserDetails和Authentication没有电子邮件。如何将字段 email 设置为“j_username”？我已经尝试过了

How to login by email instead of username in spring security

解决方案，但这还不够，因为我使用anonymousUser

另外，我有一个 UserDetailsS​​ervice 的实现，但在调试时，作为 anonymousUser 时不会调用它

public class DomainUserDetailsService implements UserDetailsService {


    private final UserRepository userRepository;

    public DomainUserDetailsService(UserRepository userRepository) {
        this.userRepository = userRepository;
    }

    @Override
    public UserDetails loadUserByUsername(final String login) {
        String lowercaseLogin = login.toLowerCase(Locale.ENGLISH);
        Optional<User> userFromDatabase = userRepository.findOneByLogin(lowercaseLogin);
        return userFromDatabase.map(user -> {
            if (!user.getActivated()) {
                throw new UserNotActivatedException("User " + lowercaseLogin + " was not activated");
            }
            List<GrantedAuthority> grantedAuthorities = user.getAuthorities().stream()
                .map(authority -> new SimpleGrantedAuthority(authority.getName()))
                .collect(Collectors.toList());
            return new org.springframework.security.core.userdetails.User(lowercaseLogin,
                user.getPassword(),
                grantedAuthorities);
        }).orElseThrow(() -> new UsernameNotFoundException("User " + lowercaseLogin + " was not found in the " +
            "database"));
    }
}

Answer 1

为了实现您的目标，您必须控制匿名用户的行为。我之前遇到过这个问题，当用户登录时查询工作正常。正如 M. Denim 建议您应该在此处通过电子邮件搜索 -> Optional<User> userFromDatabase = userRepository.findOneByEmail(lowercaseLogin);
但如果是getCurrentUserLogin()中的匿名用户你必须编写一个 if 语句来返回 anonymous@localhost如果userName = anonymousUser