c++ - 如何从 C++ 中的字符串数组中提取整数

Question

给定一个数组

char* timePeriod= {"6AM#8AM","11AM#1PM","7AM#3PM","7AM#10AM","10AM#12PM"};

如何提取以下形式的整数数组中的开始和结束时间:

start_time={6,11,7,7,10}
end_time={8,1,3,10,12}

Answer 1

您可以使用“sscanf”来做到这一点。并且不要忘记将其标记为有用 :)

#include <stdio.h>
int main() 
{
    int a,b,i;
    int start_time[5], end_time[5];

    char *t[5] = {"6AM#8AM","11AM#1PM","7AM#3PM","7AM#10AM","10AM#12PM"};
    char *(*ptr)[5] = &t;

    for(i=0;i<5;i++)
    {
        sscanf((*ptr)[i], "%d%*[AP]M#%d%*[AP]M", &a, &b);
        start_time[i]=a;
        end_time[i]=b;
    }
    printf("Starting time : ");
    for(i=0;i<5;i++)
    {
        printf("%d ",start_time[i]);
    }
    printf("\nEnding time : ");
    for(i=0;i<5;i++)
    {
        printf("%d ",end_time[i]);
    }  
    return 0;
}
OUTPUT:
Starting time : 6 11 7 7 10 
Ending time : 8 1 3 10 12