c++ - 添加分数和类别 - Woot

Question

大家好，首先我要说的是，在发布这个问题之前我已经研究了很多类似的程序，但仍然需要一些帮助。我的问题在于加法分数类函数，我需要将一个分数加到另一个分数上。我有一个类，目前正在使用该类的实例(fractionObject 和 fractionObject2)。我分别存储我的分数，一个在 fractionObject 中，一个在 fractionObject2 中。如何将这些添加到我的分数类函数“添加”中？

任何提示将不胜感激!感谢您的宝贵时间!

#include <iostream>
#include <string>
#include <sstream>
using namespace std;

// Regular prototypes
int stringToNumber(const string &Text);
int GCD(int, int);
int LCM(int, int);

class fraction{

public: // Access Specifier
    int numerator;
    int  denominator; // Can never be 0



    // Function Prototypes
    fraction();
    void setNumDen();
    void reduce();
    void add();


};

// Member functions definitions
fraction::fraction()
{
    numerator = 0;
    denominator = 0;
}

void fraction::setNumDen()
{
    string numString;
    string denString;
    do{
        cout << "Enter a numerator and denominator of fraction 1 separated by whitespace: ";
        getline(cin, numString, ' ');
        getline(cin, denString);
        if (denString == "0")
            cout << endl << "Please enter a number that isn't zero." << endl;
    } while (denString == "0"); // Making sure denominator is not zero

    numerator = stringToNumber(numString);
    denominator = stringToNumber(denString);

}

void fraction::reduce()
{
    int leastCommonMultiple = 0;

    leastCommonMultiple = LCM(numerator, denominator);

    numerator /= leastCommonMultiple;
    denominator /= leastCommonMultiple;
}

void fraction::add()
{
    int leastComDen;

}

int main()
{

    fraction fractionObject, fractionObject2;

    fractionObject.setNumDen();
    fractionObject2.setNumDen();
    // Reducing and displaying the reduced fractions
    fractionObject.reduce();
    fractionObject2.reduce();
    cout << "Reduced Fraction 1 = " << fractionObject.numerator << "/" << fractionObject.denominator << "\t" << "Reduced Fraction 2 = " << fractionObject2.numerator << "/" << fractionObject2.denominator << endl;
    // Adding and displaying the fractions



    system("pause");
    return 0;
}

// Function to convert string to number
int stringToNumber(const string &Text)//Text not by const reference so that the function can be used with a 
{                               //character array as argument
    stringstream ss(Text);
    int result;
    return ss >> result ? result : 0;
}

// result=GCD(a,b)
int LCM(int a, int b) {
    int temp = 0;

    while (b != 0) {
        temp = b;
        b = a%b;
        a = temp;
    }
    return a;
}

// result=LCM(a,b);
int GCD(int a, int b) {
    int result = 0;

    result = a * (b / LCM(a, b));
    return result;
}

Answer 1

这里没有完整的答案，但是 add 应该有两个 const fraction& 参数并返回一个临时的 fraction 对象。您可以将其重命名为 operator+。许多库添加了一个不需要创建临时对象的 += 运算符。 C++11 允许您使用移动构造函数减少这些临时对象的开销。

至于实现，这里有一个提示:1/6 + 1/9 = (9+6)/54 = 5/18。我注意到您已经有一个 reduce 函数。