c++ - 需要帮助创建数组并在另一个函数中编辑它并将其发送回初始函数

Question

我在传递给 GenerateMap 的 int main 中创建了一个数组，然后 GenerateMap 函数遍历该数组并分配每个项目。分配每个项目后，我希望它回到 int main 以便我以后可以使用它，但我不断收到错误。几次尝试后，我按照 Thenewboston 的指示通过引用传递数组。但是我仍然在代码中遇到错误。有人可以向我解释在其他函数中创建 map 时我应该怎么做吗？

错误

---

prog.cpp: In function 'int main()':
prog.cpp:22:17: error: cannot convert 'std::string (*)[MapDimension][MapDimension] {aka std::basic_string<char> (*)[MapDimension][MapDimension]}' to 'std::string** {aka std::basic_string<char>**}' for argument '1' to 'void GenerateMap(std::string**)'
GenerateMap(&Map);
^
prog.cpp: In function 'void GenerateMap(std::string**)':
[NEW ERROR] prog.cpp:70:31: error: no match for 'operator*' (operand type is 'std::string {aka std::basic_string<char>}')
cout <<"[" << *Map[i][j] << "]" << " ";

代码

---

int main() {
string Map[MapDimension][MapDimension];
GenerateMap(&Map);

}





void GenerateMap(string *Map[]) {
  srand(time(NULL));
  string x;

for (int i = 0; i <= MapDimension-1; ++i) {

    for (int j = 0; j <= MapDimension-1; ++j) 

            {

            int random = rand() % 6;
                switch  (random) 
                {
                     case 0:
                      x = " D ";
                      break;

                      case 1:
                      x = " F ";
                      break;

                      case 2:
                      x = " P ";
                      break;

                      case 3:
                      x = " M ";
                      break;

                      case 4:
                      x = " L ";
                      break;

                      case 5:
                      x = " S ";
                      break;
                }

            Map[i][j] = x;

            cout <<"[" << *Map[i][j] << "]" << "  ";
            }
    cout << endl;

}




}

Answer 1

你需要一个分号:

string Map[MapDimension][MapDimension] 

应该是

string Map[MapDimension][MapDimension];