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c++ - 如何在 GDI 中转换一个简单的位图

转载 作者:行者123 更新时间:2023-11-30 05:32:25 25 4
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我希望能够在屏幕上移动图像。这是我显示图像的代码,但它始终显示从原点开始的图像。

void drawBitmap(HDC hdc, int x1, int y1, int x2, int y2, LPWSTR path) {
HBITMAP bmp = (HBITMAP)::LoadImage(NULL, path, IMAGE_BITMAP, SCREEN_WIDTH, SCREEN_HEIGHT, LR_LOADFROMFILE);
HGDIOBJ B1 = CreatePatternBrush(bmp);
SelectObject(hdc, B1);
Rectangle(hdc, x1, y1, x2, y2);
DeleteObject(B1);
}

谢谢 Barmak Shemirani 的回答。对于任何对我的代码现在的样子感到好奇的人,我已经用回答我问题的人的代码替换了原始代码,现在它看起来像这样:

HBITMAP hbitmap = (HBITMAP)LoadImage(NULL, path, IMAGE_BITMAP, x2-x1, y2-y1, LR_LOADFROMFILE);
HDC memdc = CreateCompatibleDC(hdc);
SelectObject(memdc, hbitmap);
BitBlt(hdc, x1, y1, x2, y2, memdc, 0, 0, SRCCOPY);
DeleteDC(memdc);

最佳答案

创建一个子窗口并覆盖 WM_NCHITTEST 以返回 HTCAPTION,这将导致子窗口在单击时在主窗口周围移动。

接下来就是在子窗口中绘制位图

#include "windows.h"

LRESULT CALLBACK wndProc(HWND hwnd, UINT msg, WPARAM wp, LPARAM lp)
{
if (msg == WM_DESTROY)
{
PostQuitMessage(0);
return 0;
}
return DefWindowProc(hwnd, msg, wp, lp);
}

LRESULT CALLBACK bitmapProc(HWND hwnd, UINT msg, WPARAM wp, LPARAM lp)
{
if (msg == WM_NCHITTEST)
{
return HTCAPTION;
}

if (msg == WM_PAINT)
{
PAINTSTRUCT ps;
HDC hdc = BeginPaint(hwnd, &ps);

RECT rc;
GetClientRect(hwnd, &rc);
HBITMAP hbitmap = (HBITMAP)LoadImage(NULL, L"c:\\test\\test.bmp", IMAGE_BITMAP, 0, 0, LR_LOADFROMFILE);

HDC memdc = CreateCompatibleDC(hdc);
HBITMAP saveOldBitmap = (HBITMAP)SelectObject(memdc, hbitmap);
BitBlt(hdc, 0, 0, rc.right, rc.bottom, memdc, 0, 0, SRCCOPY);

SelectObject(memdc, saveOldBitmap); //add this
DeleteObject(hbitmap); //*** add this, important
DeleteDC(memdc);

EndPaint(hwnd, &ps);
}

return DefWindowProc(hwnd, msg, wp, lp);
}

int WINAPI wWinMain(HINSTANCE hInstance, HINSTANCE, LPTSTR, int)
{
WNDCLASSEX wcex = { sizeof(WNDCLASSEX) };
wcex.style = CS_HREDRAW | CS_VREDRAW;
wcex.hInstance = hInstance;
wcex.hCursor = LoadCursor(NULL, IDC_ARROW);
wcex.hbrBackground = (HBRUSH)(COLOR_BTNFACE + 1);
wcex.lpszClassName = L"mainWnd-bitmapWnd";
wcex.lpfnWndProc = wndProc;
if (!RegisterClassEx(&wcex))
{
MessageBox(0, L"error 1", 0, 0);
}

HWND hmain = CreateWindow(wcex.lpszClassName, L"w32", WS_CLIPCHILDREN | WS_VISIBLE | WS_OVERLAPPEDWINDOW, 0, 0, 300, 200, 0, 0, hInstance, 0);

wcex.lpszClassName = L"bitmapWnd";
wcex.lpfnWndProc = bitmapProc;
if (!RegisterClassEx(&wcex))
{
MessageBox(0, L"error 2", 0, 0);
}

CreateWindow(wcex.lpszClassName, L"w32", WS_VISIBLE | WS_CHILD | WS_BORDER, 0, 0, 50, 50, hmain, 0, hInstance, 0);

MSG msg;
while (GetMessage(&msg, NULL, 0, 0))
{
TranslateMessage(&msg);
DispatchMessage(&msg);
}

return (int)msg.wParam;
}

更改 BitBlt 中的 X/Y 位置以在不同位置打印位图

关于c++ - 如何在 GDI 中转换一个简单的位图,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/35121973/

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